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babunello [35]
2 years ago
15

The intermolecular forces of attraction in hydrogen gas are stronger than those of helium

Chemistry
1 answer:
Gekata [30.6K]2 years ago
6 0

Answer:

A

Explanation:

I think this is true letter a

You might be interested in
Calculate the mass of ZnCl2 produced by the reaction of 49.8 grams of H2. Zn + 2HCl ZnCl2 + H2
tester [92]

Answer:

3300.85 g

Explanation:

Given data:

Mass of ZnCl₂ produced = ?

Mass of H₂ produced = 49.8 g

Solution:

Chemical equation:

Zn + 2HCl     →    ZnCl₂ + H₂

Number of moles of  H₂:

Number of moles = mass/molar mass

Number  of moles = 49.8 g/ 2.056 g/mol

Number  of moles = 24.22 mol

Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.

                         H₂              :              ZnCl₂

                          1                :                   1

                        24.22         :              24.22

Mass of ZnCl₂:

Mass = number of moles × molar mass

Mass =  24.22 × 136.286 g/mol

Mass = 3300.85 g

6 0
2 years ago
How many cm3 are contained in 3.83 x 107 mm3?
gulaghasi [49]

Answer:

3.38 x 10⁴cm³

Explanation:

Given that:

      Volume of the substance  = 3.83 x 10⁷mm³

The problem entails use to convert from mm³ to cm³;

                    1000mm³   = 1cm³

So;

          3.83 x 10⁷mm³ will produce \frac{ 3.83 x 10^{7} }{1000}    = 3.38 x 10⁴cm³

5 0
3 years ago
What mass of water will change its temperature by 3.0 0C when 525 J of heat is added to it? The specific heat of water is 4.184
pav-90 [236]

Answer:

Mass of water = 41.8 g

Explanation:

Given data:

Mass of water = ?

Change in temperature = 3.0 °C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = 525 j

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 3.0°C

Now we will put the values in formula.

525 J = m × 4.184 j/g.°C  × 3.0°C

525 J = m × 12.552 j/g

m =  525 J/ 12.552 j/g

m = 41.8 g

4 0
3 years ago
When a catalyst is added to a reversible reaction in equilibrium state the value of equilibrium constant
Sergio [31]

Explanation:

The value of equilibrium constant doesn't change when a catalyst is added.

Equilibrium constant depends on Concentration of reactants , Pressure and Temperature.

6 0
2 years ago
PLEASE HELP WITH THESE!! I’m stuck
ludmilkaskok [199]
3. B
4. A
5.A
6. A (i think)
Hope this helps
4 0
3 years ago
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