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Physics

2 answers:

jolli1 [7]3 years ago

8 0

Here is a example of Newton

masya89 [10]3 years ago

3 0

Newton's 2nd law of motion: Force = (mass) x (acceleration)

You need to find the acceleration, so divide each side by (mass):

Acceleration = (Force) / (mass)

Plug in the numbers you know from the question:

Acceleration = (300,000 Newtons) / (20,000 kilograms)

Acceleration = 15 m/s²

This is a huge acceleration. It's 53% faster than a falling rock (gravity).

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Freddie drives his car 10 km North. He stops for gas and then drives 5 km South.

fgiga [73]

Answer:

5 km

Explanation:

displacement is the straight line distance from a particular point. since north and south are in opposite directions, it means that he has taken a u-turn

thus, 10 - 5 = 5km displacement

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3 years ago

Assume that a cloud consists of tiny water droplets suspended (uniformly distributed,

aev [14]

9.8 ms^-2 is acceleration

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3 years ago

A bullet is fired into the air at an angle of 45°. How far does it travel before it is 1,000 feet above the ground? (Assume that

Readme [11.4K]

Answer:

It travels 1414 feets.

Explanation:

Let's take the length the bullet travels l as the hypotenuse of a right triangle and the height it reaches one of its sides. Since we got the angle α at which it was fired and the height h it reached, we can calculate l using the sin(α) function:

$sin(\alpha )=\frac{opposite side}{hypotenuse}\\sin(\alpha)=\frac{h}{l}\\l=\frac{h}{sin(\alpha)}$

Replacing:

$l=\frac{1000ft}{sin(\frac{\pi}{4})}$

Solving and roundin to the nearest foot:

$l=1414 ft$

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4 years ago

A ball is thrown vertically upwards from the edge of the cliff and hits the ground at the base of the cliff with a speed of 30 m

olya-2409 [2.1K]

To solve this problem we will apply the linear motion kinematic equations. From the definition of the final velocity, as the sum between the initial velocity and the product between the acceleration (gravity) by time, we will find the final velocity. From the second law of kinematics, we will find the vertical position traveled.

$v = v_0 -gt$