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Anit [1.1K]
3 years ago
13

Can you describe how and why the molecules move from one side to the other?

Physics
1 answer:
Ostrovityanka [42]3 years ago
6 0
I don’t know the answer but try khan academy it’s very helpful with all subjects and is free
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A maintenance worker wants to torque an engine bolt to 65.0 N m. If the torque wrench is 35cm in length, what is force applied t
harina [27]

Answer:

Force = 186 N

Explanation:

Torque is the rotational equivalent of linear force. It can be easely calculated using the formula :

Torque = \vec{r} \times \vec{F}

Where \vec{r} is a vector that from the origin of the coordinate system to the point at which the force is applied (the position vector), \vec{F} is the applied force.

The easiest way of computing the force is by setting the origin of the coordinate system to the lowest point of the torque wrench.  By doing this we have that r (the magnitud of the position vector) is 35cm.

Before computing the force we need to set all our values to the international system of units (SI). The torque is already in SI. The one missing is the length of the torque wrench (it is in centimeters and we need it in meters). So :

35cm * \dfrac{1m}{100cm} = 0.35m

Now using the torque formula:

Torque = \vec{r} \times \vec{F}

Torque = rFsin(\theta)}

Where \theta is the smaller angle between the force and the position vector. Because the force is applied perpendiculary to the position vector  \theta = 90°, thus :

Torque = rFsin(\theta)}

65 N m = (0.35m)Fsin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

F = \dfrac{65N m} {(0.35m)sin(90°)}

F = \dfrac{1300} {7}N

so the force is approximately 186 N.

4 0
4 years ago
One of the most effective ways to evaluate data is to try to replicate it.
zubka84 [21]
I believe the answer is False 
6 0
3 years ago
In the sum A→+B→=C→, vector A→ has a magnitude of 13.6 m and is angled 40.2° counterclockwise from the +x direction, and vector
il63 [147K]

Answer:

|B|=27.00425726m

\alpha =210.3781372°

Explanation:

Let's use the component method of vector addition:

A_x=13.6cos(40.2)=10.38762599\\A_y=13.6sin(40.2)=8.778224553\\Cx=13.8cos(20.7+180)=-12.90912763\\Cy=13.8sin(20.7+180)=-4.877952844

Now, we know:

C_x=A_x+B_x\\\\C_y=A_y+b_y

So:

B_x=C_x-A_x=-23.29675362\\B_y=C_y-A_y=-13.6561774

Now lets calculate the magnitude of the vector B:

|B|=\sqrt{(B_x)^{2} +(B_y)^{2}  }=27.00425726m

Finally its angle is given by:

\alpha =(arctan(\frac{B_y}{B_x}))+180=30.37813438+180=210.3781344°

Keep in mind that I added 180 to the angles of C and B to find the real angles measured from the + x axis counter-clock wise.

8 0
3 years ago
How does the wavelength emitted by an object relate to its temperature?
OlgaM077 [116]

Explanation:

I haven't actually seen the answer I'm looking for but I think the answer is when temperatures are lower the wavelength is longer

8 0
3 years ago
A cyclist racing in the keiran is riding at the top of the track at 5m/s. Then he sprints downhill in the sprinting to the finis
kumpel [21]
The cyclist is moving by uniformly accelerated motion, with an initial velocity of v_i=5~m/s and an acceleration of a=9~m/s^2. 
The acceleration is given by
a= \frac{v_f-v_i}{\Delta t}
where v_f is the final velocity and \Delta t is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
v_f=v_i + a \Delta t=5~m/s+9~m/s^2 \cdot 1.75~s=20.75~m/s
6 0
4 years ago
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