First one: If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV. It's an even function. The fourth graph represents it.
If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Answer:cost of each pound of apple= $3
And cost of each pound of orange =$2
Step-by-step explanation:
Step 1
Let cost of apples = x
And cost of Oranges =y
Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as
6 x + 3y= 24----- equation 1
Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as
5x+ 4y= 23----- equation 2
Step 2
6 x + 3y= 24----- equation 1
5x+ 4y= 23----- equation 2
Using substitution method to solve the equation
6 x + 3y= 24
24-6x=3y
y= 24-6x/3 = 8-2x
Y= 8-2x
Substituting the value of y= 8-2x into equation 2
5x+ 4( 8-2x)= 23
5x+ 32 -8x= 23
32-23= 8x-5x
9=3x
x=9/3
x=3
Putting the value of x= 3 in equation 1 and solving to find y
6 x + 3y= 24
6(3) +3y= 24
18+3y=24
3y= 24-18
3y=6
y=6/3= 2
Therefore the cost of each pound of apple= $3
And cost of each pound of orange =$2
608
607.5
.5 rounds up to 1
607+1=608
