3 years ago

Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

1 answer:

3 0

<span>J(–3, 11) and K(1, –3)
Slope = (11 + 3)/(-3 - 1) = 14/-4 = -7/2

Equation
y + 3 = -7/2(x - 1)
2y + 6 = -7x + 7
2y = -7x + 1
7x + 2y = 1 ....This is standard form (Ax + By = C)

Hope it helps.</span>

You might be interested in

what are the coordinates of the midpoint of the line segment with endpoints B(9, -8) C(2, -5) ANSWER BY TODAY PLEASE

qwelly [4]

Y2-y1 -5-(-8) 3
____ = _____ = ___ = -3/7
x2-x1 2-9 -7

4 0

3 years ago

What is the slope of the line?

spin [16.1K]

Answer: 2

Step-by-step explanation:

The slope of a line is $\frac{rise}{run}$ (rise over run)

This means for every point you must go up/down to get your next point you divide it by every point you go right/left.

From one point to the next it goes up 2 (rise) and right 1 (run)

$\frac{2}{1} = 2$ so that is your slope

8 0

2 years ago

What is 3 divided by 1/5 :(

scZoUnD [109]

Answer:

Step-by-step explanation:

that's what gogle said

8 0

2 years ago

Read 2 more answers

Help & explain answer pls

AlekseyPX

The solution is (-2,4) she right both have the same solution because if you solve both of them you will get (-2,4)

5 0

2 years ago

Mandy is trying to subtract 7 − 12, and she has asked you for help. How would you explain the process of solving the problem to

xz_007 [3.2K]

Answer:

-5 am sorry Dear I ca'nt sed a pic , I didn't see the option

3 0

3 years ago

Read 2 more answers