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aalyn [17]
3 years ago
6

Two shapes that have the same shape and size

Mathematics
2 answers:
vivado [14]3 years ago
7 0
Squares and rectangles
stellarik [79]3 years ago
6 0

Answer:

they are congruent

Step-by-step explanation:

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S.O.S help !!!!!!!!!!!!!!!!
inessss [21]

after 4 days 88 boats  will have passes under the bridge


3 0
3 years ago
Read 2 more answers
Please, quickly. Sorry for the poor picture quality.
Nimfa-mama [501]

Answer:

<2 is 50º

Step-by-step explanation:

you first want to find what x is, so you would put the two equations in an (equation)=(equation) and get x and the number across from each other, that would be x=15º. you then plug in the 15 to the equation, and solve that, resulting in 130º. The angle is going to be 180 in total, so subtract the 130º from 180º and you would get 50º

3 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
Which of the following shows a circle circumscribed about a triangle?
Dima020 [189]

Answer: The first option.

Step-by-step explanation:

1. By definition,  when a circle circumscribed about a triangle it passes through all the vertices of that triangle (As you know, a triangle has three vertices).

2. As you can see in the figure attached, the only circle that passes through three vertices of the triangle is the the circle of the first optin. Therefore, you can conclude that that circle is circumscribed about the triangle.

5 0
3 years ago
Square root 7x+16 +4=x
gavmur [86]
1     Simplify 7x+16+47x+16+4 to 7x+207x+20<span>    7x+20=x<span>7x+20=x</span></span>
2     Subtract 7x from both sides<span>    20=x-7x<span>20=x−7x</span></span>
3 Simplify <span>x-7x<span>x−7x</span></span> to <span>-6x<span>−6x</span></span>
<span>20=-6x<span>20=−6x</span></span>
4     Divide both sides by −6    -20/6=x
5     Simplify 20/6 to 10/3     -10/3=x
6     Switch sides
    x=-10/3<span><span><span>     </span></span></span>
6 0
3 years ago
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