a. The graph is concave up in the interval 0 ≤ x ≤ +∞
b. The graph is concave down in the interval -∞ ≤ x ≤ 0
To answer the question, we need to know what intervals are
<h3>What are intervals?</h3>
Intervals are range of values in which a function is valid. It can either be the range of values of input or output of the function.
<h3>a. Interval where the graph is concave up</h3>
From the graph, we see that the function is concave up in the interval 0 ≤ x ≤ +∞
So, the graph is concave up in the interval 0 ≤ x ≤ +∞
<h3>b. Interval where the graph is concave down</h3>
From the graph, we see that the function is concave down in the interval -∞ ≤ x ≤ 0
So, the graph is concave down in the interval -∞ ≤ x ≤ 0
Learn more about intervals here:
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For the parabola:
h(t) = -at2 + bt, the maximum occurs at -b/2a
For h(t) = -16t2 + 576t that is -576/(-2)(-16), or -576/32, or 18.
The projectile is at its highest point at 18 seconds.
The answer to the question is B
Answer:
x= 127
w = 53
Step-by-step explanation:
Answer: $4.50
Step-by-step explanation:
6+6+3.5= 15.5 paid with a 20 so 4 dollars and 50 cents change