Ayuda!!!! ..........................................................

Physics

1 answer:

kobusy [5.1K]3 years ago

8 0

Answer: the answer would be 200v I'm pretty sure :)

Explanation:

You might be interested in

Suppose you are an astronomer, and a child asks you to explain the light given off by stars. In your own words, describe the rel

Nadya [2.5K]

Well, i would tell the kid that light is electromagnetic radiation which is visible. The frequency and wavelength is just right so the radiation becomes visible, and that visible radiation goes away from the star and reaches earth It also depends on the age of the child and the comprehension level

3 0

3 years ago

Read 2 more answers

Describe three ways that adults continue to guide children's emotions during the school-age

wolverine [178]

1. Always be the bigger person
2. Violence is never the answer
3. Don’t fight fire with fire

6 0

3 years ago

How much min the basketball 1 player play

Sedbober [7]

Answer:

A professional basketball game depends on the association presiding over the game. An NBA game lasts for 48 minutes whereas FIBA games take 40 minutes. The total time taken to play for any specialized game is over 2 hours 15 minutes. The time includes the time disruptions like fouls, timeouts, and breaks.

<em>I hope it helps you...</em>

3 0

3 years ago

Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the

scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = $\frac{kQ_{1}Q_{2} }{r^{2} }$