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Zepler [3.9K]
3 years ago
15

Write the balanced COMPLETE ionic equation for the reaction when Na₂CO₃ and AgNO₃ are mixed in aqueous solution. If no reaction

occurs, write only NR.

Chemistry
1 answer:
Vinil7 [7]3 years ago
8 0
Hope I helped with the answer to your question ;)

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Write the formula for the compound formed between potassium and sulfur. ks ks2 k2s k2so3 k3s2
Mars2501 [29]
The answer should be K2S
6 0
3 years ago
Write the formula for a complex formed between co3 and nh3, with a coordination number of 6.
hammer [34]
In complex compounds coordination number is the number of atoms or polyatomic ions surrounding the central metal. In given statement the coordination number given is 6, means there are 6 ligands surrounding the metal atom, and the ligands given are only NH₃, so 6 NH₃ molecules are surrounding the Cobalt atom. Hence,

                                              [Co (NH₃)₆]
As, NH₃ is neutral so the charge on sphere will be the charge on Co, as charge given in statement id +3 so,

                                               [Co (NH₃)₆]³⁺

Name of this complex is as follow,

                                    Hexaamminecobalt (III) Ion
6 0
3 years ago
Calculate the molarity of 65.3 grams of sugar(342.3 g/mol), c12h22011 in 750 ml of solution.
k0ka [10]

Answer:

0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>

8 0
2 years ago
How many grams of ethanol would be formed from the reaction of 243.7<br> grams of glucose?
Aneli [31]

Answer:

5 billion times

Explanation:

4 0
3 years ago
How is an average mass different from a weighted mass
romanna [79]

In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.

Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.

<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>

<em>Weighted average (Method 1) </em>

Use the <em>numbers of each</em> gender (15 girls + 5 boys) ,

Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20

= 1120 kg/20 = <em>56 kg</em>.

If you put all the students on one giant balance, their total mass would be

1120 kg and the average mass of a student would be <em>56 kg. </em>

<em>Weighted average (Method 2) </em>

Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).

Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>

Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.

6 0
3 years ago
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