Answer:
Step-by-step explanation:
Domain x^2 - 9 {Solution: - infinity < x < infinity}
Interval notation (- infinity, infinity)
Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)
Interval notation (-9, infinity)
Axis interception points of x^2 - 9:
X- intercepts (3, 0) (-3, 0)
Y-intercepts (0, -9)
Vertex of x^2 - 9: Minimum (0, -9)
Solve for f:
f (x) = x^2 - 9
Step 1: Divide both sides by x.
fx / x = x^2 - 9 / x
f = x^2 - 9 / x
Answer:
f = x^2 - 9 / x
The area of a kite is (1/2) * x * y, where x and y are the length of the two diagonals. In this case, the length of the two diagonals are 10 ft and 2 ft.
<span>Plug that in the equation, we get 1/2 * 2 * 10. We multiply the 2 and 10 first to get 20, that leaves us with 1/2 x 20, which is 10, so the area of this kite is 10 ft squared.</span>
Y = mix + b would be slope intercept for. your y intercept would be B which is the line that crosses that y intercept your Mx would be a fraction for point slope form like if your slope would be 1 over 2 you would fo up and left twice because of rise over run
Answer:
Look below
Step-by-step explanation:
lets have -29 be y2 and -5 be x2
21 - (-)29
5 - (-)5
Subtracting a negative is just adding it so
21 + 29 50
5 + 5 10
50/10
this simplified, is 5/1 or 5
y=5x+b
now we need to find b, so we substitute y and y
x = 5
y = 21
21=5*5=b
5*5 is 25
now we need to get to 21
25 -4 is 21
b = -4
y=5x-4
