Answer:
The net ionic equation is
2PO₄³⁻ + 3Ca²⁺ → Ca₃(PO₄)₂ (s)
Written in words, the net ionic equation is
2 upper P upper O subscript 4 superscript 3 minus, plus 3 upper C a superscript 2 plus right arrow upper C a subscript 3 (upper P upper O subscript 4) subscript 2.
Option B.
Explanation:
The equation described, written down is
6Na⁺ + 2PO₄³⁻ + 3Ca²⁺ + 6Cl⁻ → 6Na⁺ + 6Cl⁻ + Ca₃(PO₄)₂
To obtain the net ionic equation, we examine the reaction and eliminate the ions that occur on both sides of the equation.
On checking this reaction, we see that 6Na⁺ and 6Cl⁻ are the ions that occur on both sides. They are thus, eliminated.
It becomes clear that the overall reaction is a reaction of aqueous Na₃PO₄ with aqueous CaCl₂ to give aqueous NaCl and insoluble Ca₃(PO₄)₂.
The aqueous compounds exist in ionic form in solutions, hence, the net ionic equation of the double displacement reaction after eliminating the ions that remain in solution before and after the reaction, we obtain
2PO₄³⁻ + 3Ca²⁺ → Ca₃(PO₄)₂ (s)
Better written as
3Ca²⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ (s)
The net ionic equation written in words is
2 upper P upper O subscript 4 superscript 3 minus, plus 3 upper C a superscript 2 plus right arrow upper C a subscript 3 (upper P upper O subscript 4) subscript 2.
Hope this Helps!!!
