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AnnyKZ [126]
4 years ago
15

I need to show work on solving a problem like 1.8 ×2.8

Mathematics
1 answer:
wlad13 [49]4 years ago
4 0

Answer:

5

Step-by-step explanation:

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PLZ HELP ASAP!!
zysi [14]

Answer:

b

Step-by-step explanation:

8 0
4 years ago
Solve the equation -9v-9=-27 for v.
Nikolay [14]

Answer:

v=2

Step-by-step explanation:

-9v-9=-27

add nine to both sides

-9v-9+9=-27+9

simplify

-9v=-18

divide both sides by -9

-9v/-9   -18/-9

simplify y=2

hope this helps :) have a nice day !!

4 0
3 years ago
Read 2 more answers
Moesha has 196 pepper plants that she wants to plant in square formation. How many peppers plants should she plant in each row?
miss Akunina [59]

Hey there!!

In order to solve this question, we take the area as 196 as these are the total number of plants to cover a specific place.

The formation must be in a square formation

area of a square = ( s ) ²

s = side

or the number of plants in a row

s² = 196

s = √196

s = 14

There are 14 plants in each row

Hope my answer helps!

8 0
3 years ago
Read 2 more answers
If the point (2, -10) lies on the graph of a direct variation, which represents the direct variation equation?
Zanzabum

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2},\stackrel{y}{-10})~~ \textit{we know } \begin{cases} x=2\\ y=-10 \end{cases}\implies -10=k2\implies \cfrac{-10}{2}=k\implies -5=k \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-5x~\hfill

8 0
3 years ago
What is the relationship between angle BAC and angle BOC?
Basile [38]

In this problem, an angle like angle BAC where the vertices like on the circle itself is called the inscribed angle.

While angle BOC, where O is the center of the circle, is called the central angle.

Using  Proposition III.20 from Euclid's Elements, this is called the Inscribed Angle Theorem  wherein:

∠BOC = 2∠BAC

or ∠BOC / 2 = ∠<span>BAC</span>

3 0
3 years ago
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