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Anika [276]
3 years ago
9

How would you define Acid

Chemistry
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

a chemical substance that neutralizes alkalis, dissolves some metals, and turns litmus red; typically, a corrosive or sour-tasting liquid of this kind.

Explanation:

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If 200 g of benzoyl peroxide are used with 38 Kg of PTFE monomer, calculate the expected molecular weight of the polymer if (i)
den301095 [7]

Explanation:

The molecular weight of benzoyl peroxide is 242.23 g/mol.

Therefore, number of moles present in 200 g of benzoyl peroxide are as follows.

            No. of moles = \frac{mass}{\text{molar mass}}

                                  = \frac{200 g}{242.23 g/mol}

                                  = 0.825 mol

Molecular weight of PTFE is 100 g/mol.Hence, calculate the number of moles of PTFE in 38 kg as follows.

As 1 kg = 1000 g. So, 38 kg = 38000 g.

             No. of moles = \frac{mass}{\text{molar mass}}

                                  = \frac{38000 g}{100 g/mol}

                                  = 380 mol

As it is given that the initiator is 15% active. So, actual number of moles of benzoyl peroxide are as follows.

                        0.15 \times 0.826

                           = 0.124 mol

For combination, 1 mol of benzoyl peroxide produces 1 chain. Therefore, degree of polymerization will be calculated as follows.

                    DP = \frac{380 mol}{0.124 mol}    

                          = 3065.33 mol

Average molecular weight of monomer is as follows.

       \frac{0.124}{0.124 + 380} \times MW_{benzoyl} + \frac{380}{0.124 + 380} \times MW_{PTFE}

       = 100.05 g/mol

Therefore, calculate the expected molecular weight of polymer as follows.

                   3065.33 \times 100.05 g/mol

                     = 306675.23 g/mol

Hence, for disproportion 1 mole benzoyl peroxide produces 2 chains.

                     DP = \frac{2 \times 380}{0.124}

                           = 6129.03

Therefore, calculate the expected polymer weight as follows.

                     6129.03 \times 100.05

                   = 613209.68 g/mol

Thus, we can conclude that the the expected polymer weight is 613209.68 g/mol.

6 0
3 years ago
The combustion of glucose (c6h12o6) with oxygen gas produces carbon dioxide and water. this process releases 2803 kj per mole of
V125BC [204]

Answer:- 335 kcal of heat energy is produced.

Solution:- The balanced equation for the combustion of glucose in presence of oxygen to give carbon dioxide and water is:

C_6H_1_2O_6+6O_2\rightarrow 6CO_2+6H_2O

From given info, 2803 kJ of heat is released bu the combustion of 1 mol of glucose. We need to calculate the energy produced when 3.00 moles of oxygen react with excess of glucose.

We could solve this using dimensional analysis as:

3.00mol O_2(\frac{1mol glucose}{6mol O_2})(\frac{2803 kJ}{1mol glucose})

= 1401.5 kJ

Now, let's convert kJ to kcal.

We know that, 1kcal = 4.184kJ

So, 1401.5kJ(\frac{1kcal}{4.184kJ})

= 335 kcal

Hence, 335 kcal of heat energy is produced by the use of 3.00 moles of oxygen gas.


8 0
3 years ago
A chemist prepares a solution of barium chloride by measuring out of barium chloride into a volumetric flask and filling the fla
mezya [45]

The given question is incomplete. The complete question is:

A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.

Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times }{V_s}

where,

n = moles of solute

V_s = volume of solution in L

moles of BaCl_2(solute) = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{110g}{208g/mol}=0.529mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.529\times 1000}{440ml}=1.20mole/L

Therefore, the molarity of solution is 1.20 mol/L

8 0
3 years ago
A student has an unknown sample. How can spectroscopy be used to identify the sample?
iogann1982 [59]

Answer: A. It can identify the elements in the sample.

Explanation: on edge

4 0
3 years ago
Why is Anton Von Leeuwenhoek important in the cell theory?​
vesna_86 [32]

Answer:

He was the first scientist to observe and describe bacteria and protozoa by looking at a drop of water from a pound under a microscope. He also was the one to build the first compound microscope.

Hope this helps :)

4 0
3 years ago
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