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Flura [38]
4 years ago
8

If a certain material heats up quickly and cools down quickly, the material likely has

Physics
1 answer:
GenaCL600 [577]4 years ago
7 0

Low specific heat in the material

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Calculate the kinetic energy of a 5.2 kg object moving at 2.4 m/s.​
Lilit [14]

Answer:

Kinetic energy, K = 14.97 J

Explanation:

We have,

Mass of the object, m = 5.2 kg

Velocity of the object, v = 2.4 m/s

It is required to find the kinetic energy of the object. As it is moving with some velocity, it will have kinetic energy. It is given by :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5.2\times (2.4)^2\\\\K=14.97\ J

So, the kinetic energy of the object is 14.97 J.    

7 0
3 years ago
A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ
ra1l [238]

Answer:

The correct question is:

"Find the energy each gains"

The energy gained by a charged particle accelerated through a potential difference is given by

\Delta U = q\Delta V

where

q is the charge of the particle

\Delta V is the potential difference

For a proton,

q=+e=1.6\cdot 10^{-19}C

And since \Delta V=100 V

The energy gained by the proton is

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

For an alpha particle,

q=+2e=3.2\cdot 10^{-19}C

Therefore, the energy gained is

\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

q=+e=1.6\cdot 10^{-19}C

So the energy gained is the same as the proton:

\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J

6 0
3 years ago
Why is oxygen gas usually stored in metal cylinders?
olga2289 [7]
The reason oxygen and other gasses are stored in metal cylinders is that of the simple fact it's a gas.  The reasoning behind it is to safely store the gas with no leaking etc.

"The purpose of this safety policy and procedure is to establish guidelines for the protection and safety of ([COMPANY]) employees who handle and use compressed gases. Compressed gases are typically stored under pressure in metal cylinders. These cylinders are designed and constructed to withstand high pressures. Improper handling and use of compressed gases can result in devastating consequences.

This safety policy and procedure provide guidelines for the safe handling and use of compressed gases. It includes provisions for training and presents safe handling guidelines. It also presents the types, uses, inspection, and marking requirements of compressed gas cylinders. Additionally, this safety policy and procedure present transportation and storage requirements for compressed gas cylinders."


quoted answers belong to: 


<span>https://www.safetyinfo.com/written-safety-programs-compressed-gas-cylinder-safety-program-free-index...
</span>


I take NO CREDIT in this answer.  All quoted answers are copied from the link above,  I am only here to help, not to get into trouble.  

4 0
3 years ago
Read 2 more answers
What is the maximum height achieved if a 0.600 kg mass is thrown straight upward with an initial speed of 75.0 m·sâ1? ignore th
loris [4]

We can solve the problem by using the law of conservation of energy:

- at the beginning, all mechanical energy of the object is just kinetic energy: K=\frac{1}{2}mv^2, where m is the mass and v is the velocity

- at the point of maximum height, all mechanical energy of the object is just gravitational potential energy: U=mgh, where h is the maximum height

Therefore, the conservation of energy becomes:

\frac{1}{2}mv^2 = mgh

Re-arranging, we find the maximum height:

h=\frac{v^2}{2g} = \frac{(75.0 m/s)^2}{2(9.8 m/s^2)}=287.0 m


6 0
3 years ago
A particle of mass, m = 3.0kg movers with a uniform velocity, v = (5m/s)I +(3m/s)j. At the time, t, the particle passes through
quester [9]

Answer:

The magnitude is 63 kg m²/s, and the direction is -k.

Explanation:

Plug the values into the equation:

L = m v×r

L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)

Take the cross product.  The cross product of two dimensional vectors is:

<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>

Therefore:

L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>

L = (3.0 kg) <-21 k m²/s>

Multiply:

L = <-63 k kg m²/s>

The magnitude is 63 kg m²/s, and the direction is -k.

6 0
3 years ago
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