Answer:
The net force on the car is 2560 N.
Explanation:
According to work energy theorem, the amount of work done is equal to the change of kinetic energy by an object. If '' be the work done on an object to change its kinetic energy from an initial value '' to the final value '', then mathematically,
where '' is the mass of the object and '' and '' be the initial and final velocity of the object respectively. If '' be the net force applied on the car, as per given problem, and '' is the displacement occurs then we can write,
Given, .
Equating equations (I) and (II),
Answer:
The mass of the second weight is approximately 0.477 kg
Explanation:
The given parameters are;
The acceleration experienced by the two weights = 3.8 m/s²
The mass of the first weight = 1.08 kg
The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;
Where;
a = The common acceleration of the two weights
g = The acceleration due to gravity = 9.81 m/s²
M = The mass of the first weight = 1.08 kg
m = The mass of the second weight
Therefore, we have;
The mass of the second weight = m ≈ 0.477 kg
The mass of the second weight ≈ 0.477 kg.
The answer is "b" a circuit.
Answer:
2
Explanation:
there are 2 significant figures in there