14 bc the 0.610 is rounded
Answer:
0.09425
Explanation:
The reactant is in solid phase and therefore has zero partial pressure.
The products have the same mole ratio (1:1) and will have the same partial pressure = 1/2 × 0.614 atm = 0.307 atm
Kp = (NH3)(H2S) = 0.09425
Hi my dear friend,
How to find mass of hydrate?
Divide the mass of your anhydrous (heated) salt sample by the molar mass of the anhydrous compound to get the number of moles of compound present. In our example, 16 grams / 160 grams per mole = 0.1 moles. Divide the mass of water lost when you heated the salt by the molar mass of water, roughly 18 grams per mole.
~Thank you
We are given that the concentration of the KCl is 2 meq /
mL. Assuming that the ampule also has exactly this concentration, therefore:
amount of KCl in ampule = (2 meq / mL) * (20 mL)
amount of KCl in ampule = 40 meq
This amount of KCl is now inside a solution of 1 Liter (also
equivalent to 1000 mL), therefore the new concentration in the resulting
solution is:
new concentration = 40 meq / 1000 mL
new concentration = 0.04 meq / mL
Since 0.04 in decimal is 4% in percentage, therefore the
strength of the resulting solution is 4% KCl.