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3 years ago

Choose the best answer to complete the statement: Carbon atoms can bond to __________ other atoms.

1 answer:

5 0

1,2,3, or 4. Generally, carbon likes to make 4 bonds to 4 different atoms. For example, in methane(CH4), Carbon makes 4 bonds to 4 hydrogens. However, Carbon can also make double and triple bonds to atoms. This means that of the 4 bonds, more are used to bond to one thing. For example, in the compound CN, Carbon bonds to hydrogen on one side and triple bonds to Nitrogen on the other. This shows carbon can bond to at 2 atoms as well as 4 at a time. using a one double bond carbon would only bond to 3 atoms. I cant think of an example where carbon only bonds to one other atom without breaking the octet rule, but all the other values can be validated through examples. So, I still think the bottom answer is correct. Hope this helped!

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Answer:

Explanation:

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3 years ago

The value of Ka for phenol (a weak acid), C6H5OH, is 1.00×10-10. Write the equation for the reaction that goes with this equilib

I am Lyosha [343]

Answer:

$Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}$

Explanation:

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In this case, weak acids are characterized by the fact they do not dissociate completely, it means they do not divide into the conjugated base and acid at all, a percent only, which is quantified via equilibrium. In such a way, the chemical equation representing such incomplete dissociation is said to be:

$C_6H_5OH\rightleftharpoons C_6H_5O^-+H^+$

Thus, we can write the law of mass action, which consider the equilibrium concentrations of all the involved species, which is also known as the acid dissociation constant which accounts for the capacity the acid has to yield hydronium ions:

$K=Ka=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OH]}$

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3 years ago

According to the following reaction, how many grams of chloric acid (HClO3) are produced in the complete reaction of 31.6 grams

gogolik [260]

Answer:

$m_{HClO_3}=12.7gHClO_3$

Explanation:

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Considering the reaction:

$3Cl_2(g)+3H_2O(l)-->5HCl+HClO_3$

The molar masses of chlorine and chloric acid are:

$M_{Cl_2}=35.45*2=70.9g/mol\\M_{HClO_3}=1+35.45+16*3=84.45g/mol$

Now, we develop the stoichiometric relationship to find the mass of chloric acid, considering the molar ratio 3:1 between chlorine and chloric acid, as follows:

$m_{HClO_3}=31.6gCl_2*\frac{1molCl_2}{70.9gCl_2} *\frac{1molHClO_3}{3mol Cl_2} *\frac{85.45g HClO_3}{1mol HClO_3} \\m_{HClO_3}=12.7gHClO_3$

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4 years ago

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Aleks04 [339]

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3 years ago

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