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3 years ago

Make a diagram showing how communication satellites could be used to relay

Chemistry

1 answer:

alexdok [17]3 years ago

6 0

Answer:

Explanation:

Satellite acts as a relay station for earth sources. A transmission station sends the information to the satellite, which in turn retransmits to the receiving stations. The original signal being transmitted from the earth station to the satellite is called uplink of 6 GHz The retransmitted signal from the satellite to the receiving station is called downlink of 4 GH frequency. The transponder is the transmitter-receiver combination in a transponder.

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Substitution and Na(No3) + Fe

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The equation to calculate mean rate of reaction g/s

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3 years ago

Witch wave is mad up of vibrating electric and magnetic fields that can move through space at the speed of light

8_murik_8 [283]

Answer:

Hiya! Your answer would be an Electromagnetic Wave.

Explanation:

Electromagnetic Wave is an electromagnetic wave that travels through space at the speed of light at about 300,000 kilometers per second. So when we talk about light traveling in waves, we can also talk about frequency, or the number of wavelengths that pass a certain point in a given length of time. We usually measure this as the number of wavelength cycles that pass per second. The units for this measurement are Hertz (hz).

So, if the wavelength of a light wave is shorter, that means that the frequency will be higher because one cycle can pass in a shorter amount of time. This means that more cycles can pass by the set point in 1 second. Likewise, a light wave that has a longer wavelength will have a lower frequency because each cycle takes a longer time to complete.

Hope I helped and I hope you get it right! :). Have a lovely day my friend!

~Bella

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3 years ago

If a temperature increase from 10.0 ∘C to 22.0 ∘C doubles the rate constant for a reaction, what is the value of the activation

maria [59]

The activation energy barrier is 40.1 kJ·mol⁻¹

Use the Arrhenius equation

$\ln( \frac{k_2 }{k_1 }) = (\frac{E_{a} }{R })(\frac{ 1}{T_1} - \frac{1 }{T_2 })\\$

$\ln( \frac{2k }{k}) = (\frac{E_{a} }{\text{8.314 J} \cdot \text{K}^{-1} \text{mol}^{-1} })(\frac{ 1}{\text{283.15 K}} - \frac{1 }{\text{295.15 K }})\\$

$\ln2 = (\frac{ E_{a} }{\text{8.314 J} \cdot \text{K}^{-1} \text{mol}^{-1}}) \times 1.436 \times10^{-4}\\$

$\ln2 = E_{a} \times 1.727 \times 10^{-5} \text{ mol} \cdot \text{J}^{-1}$

$E_{a} = \frac{\ln2 }{ 1.727 \times10^{-5}\text{ mol} \cdot \text{J}^{-1}}\\$

$E_{a} = \text{40 100 J}\cdot\text{mol}^{-1} = \textbf{40.1 kJ}\cdot \textbf{mol}^{-1}$

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3 years ago