Since there are 24 fiction books and 52 books in total, you can start with subtracting them both to find the amount of non-fiction books. 52-24=28, so 28 non-fiction books are currently checked out. Now for the fun part. There are two ways I know how to do this, so let's start. One way is that you can put a ':' between the two numbers. For example, since we are trying to find fiction books to non-fiction, we would say 24:28. The first number will represent the first thing they ask for (fiction), and the second number will represent the second thing they ask for (non-fiction). Another way to do this is by putting the numbers as a fraction. For example, you could put 24/28. It will still mean the same thing, and it will not change the outcome. I hope this helps! :)
Answer:
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Step-by-step explanation:
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The total number of stickers the 2 children had was 192 stickers.
Let x represent Mary initial stickers, y represent Gary initial stickers and z represent the total stickers.
x + y = z
They shared in the ratio of 5:3, hence:
x = (5/8)z
Mary gives 1/3 of her stickers to Gary to have 32 more stickers than her.
(1/3)x = (1/3)(5/8)z = (5/24)z
y + (1/3)x = (2/3)x + 32
Solving equation 1, 2 and 3 gives:
x = 120, y = 72, z = 192
The total number of stickers the 2 children had was 192 stickers.
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A) The answer is
x + y + z = 24
3x + 2y + z = 53
x = y + z
x - the number of swimmers in the first place
y - the number of swimmers in the second place
z - the number of swimmers in the third place
<span>1. The e-mail states that 24 individuals placed: x + y + z = 24
2. </span>First place earned 3 points, second place earned 2 points, and third place earned 1 point, <span>earning a combined total of 53 points: 3x + 2y + z = 53
3. </span><span> There were as many first-place finishers as second and third-place finishers combined: x = y + z
The system of three equations is:
</span>x + y + z = 24
3x + 2y + z = 53
x = y + z
B) The answer is
12 swimmers in the first place
5 swimmers in the second place
7 swimmers in the third place
(i) x + y + z = 24
(ii) 3x + 2y + z = 53
(iii) x = y + z
______
Substitute y + z from the third equation into the first one:
(i) x + y + z = 24
(iii) x = y + z
______
x + x = 24
2x = 24
x = 24 / 2
<u>x = 12</u>
_____
x = y + z
x = 12
y + z = 12
z = 12 - y
3x + 2y + z = 53
3 * 12 + 2y + (12 - y) = 53
36 + 2y + 12 - y = 53
2y - y + 36 + 12 = 53
y + 48 = 53
y = 53 - 48
<u>y = 5</u>
z = 12 - y
z = 12 - 5
z = 7