Answer : The molar heat of solution of KBr is 19.9 kJ/mol
Explanation :
Mass of KBr = 7.00 g
Molar mass of KBr = 119 g/mole
Heat capacity = 2.72 kJ/K
Change in temperature = 0.430 K
First we have to calculate the moles of KBr.
Now we have to calculate the heat of the reaction.
where,
q = amount of heat = ?
= heat capacity =
= change in temperature = 0.430 K
Now put all the given values in the above formula, we get:
Now we have to calculate the molar heat of solution of KBr.
where,
n = number of moles of KBr
Therefore, the molar heat of solution of KBr is 19.9 kJ/mol
C funnel because the funnel would have a large enough entrance to put a solid through
Answer:
Ice and water on the ground affect incoming solar radiation by reflecting 4 percent of solar radiation that reaches the surface.
Explanation:
Answer:
The mass of KHP present in the solution is 0.42 g.
Explanation:
This is the titration reaction:
KHP-H + NaOH → KHP-Na + H₂O
From the equation, we know that 1 mol KHP reacts with 1 mol NaOH (because KHP has one acidic hydrogen). If we know how many moles of NaOH were used to complete the reaction, we can find how many moles of KHP were present.
The moles of NaOH used can be calculated using the data provided by the problem:
moles of NaOH used = Concentration NaOH * volume of NaOH.
Molarity (M) is a concentration unit that means mol/l.
mol NaOH = 0.1000 mol/1000ml * 20.46ml = 2.046 x 10⁻³ mol
Then, since 1 mol NaOH reacts with 1 mol KHP, 2.046 x 10⁻³ mol NaOH will react with 2.046 x 10⁻³ mol KHP.
The mass of 1 mol KHP (the molar mass) is 204.22g. Then, the mass of 2.046 x 10⁻³ mol KHP will be (2.046 x 10⁻³ mol * 204.22g / 1 mol) 0.42 g
Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
- Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
- units of volume are mL, liter, cm³ or m³.
Given,
in this question, volume occupied by gas at 10.9⁰c is 733cm³.
we have to find out temperature at which gas occupies volume of 950 cm³.
First, convert temperature from celcius to Kelvin
10.9⁰c = 10.9 + 273.15 = 284.05 K
By equation or Boyle's Law
P1 x V1 / T1 = P2 x V2 / T2
Pressure is constant here
therefore, V1 / T1 = V2 / T2
here, V1 = 733 cm³
T1 = 284.05 K
V2 = 950 cm³
we have to find out T2
So, 733 / 284.05 = 950 / T2
T2 = 284.05 × 950 / 733 = 368.14 K
= 94. 99⁰c
Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
Learn more about Boyle's Law here:
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