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kolezko [41]
3 years ago
12

Use the encrypting congruence c ≡ (7p + 12) mod 26 to code the message PARALLEL LINES.

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:  PARALLEL LINES  should be coded as "TSHSRRUR RWFUO"

Step-by-step explanation:

Since we have given that

PARALLEL LINES

As we know that according to alphabets,

P is at 16

A is at 1

R is at 18

L is at 12

E is at 5

N is at 14

S is at 19

And we have given that

c \equiv(7p+12)\ mod 26

So, P becomes :

c\equiv (7\times 16+12)\ mod\ 26=124\ mod\ 26=20\ mod\ 26=T

A becomes

c\equiv (7\times 1+12)\ mod\ 26=19\ mod\ 26=S

S becomes

c\equiv (7\times 19+12)\ mod\ 26=145\ mod\ 26=15\ mod\ 26=O

L becomes

c\equiv (7\times 12+12)\ mod\ 26=96\ mod\ 26=18\ mod\ 26=R

E becomes

c\equiv (7\times 5+12)\ mod\ 26=47\ mod\ 26=21\ mod\ 26=U

I becomes

c\equiv (7\times 9+12)\ mod\ 26=75\ mod\ 26=23\ mod\ 26=W

N becomes

c\equiv (7\times 14+12)\ mod\ 26=110\ mod\ 26=6\ mod\ 26=F

R becomes

c\equiv (7\times 18+12)\ mod\ 26=138\ mod\ 26=8\ mod\ 26=H

Hence, PARALLEL LINES  should be coded as "TSHSRRUR RWFUO"

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3 years ago
A professor records the difference between the marks scored by the students in the class test last week and those scored in the
dezoksy [38]

Answer: (10.82\ , 13.18)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\mu\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 35  , large sample (n>30)

Mean difference : \overline{x}=12

Standard deviation : \sigma=3

Significance level : \alpha=- 1-0.999=0.001

Critical value : z_{\alpha/2}=z_{0.0005}=3.4807567

Now, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students will be :-

12\pm\ (3.4807567)\dfrac{2}{\sqrt{35}}\\\\=12\pm1.18\\\\=(10.82\ , 13.18)

Hence, the  99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students = (10.82\ , 13.18)

4 0
3 years ago
20 POINTS! TTM
g100num [7]

A relation is (also) a function if every input x is mapped to a unique output y.

In terms of graphical representation, this implies that a graph represents a function if there doesn't exist a vertical line that intersects the graph more than once. So:

  1. The first graph is exactly a vertical line, so it's not a function.
  2. The second graph represents the function y=x, so it's a function: you can see that every possible vertical line crosses the graph only once.
  3. The third graph is not a function, because you can draw vertical lines that cross the graph twice.
  4. Similarly, in the fourth graph you can draw vertical lines that cross the graph twice
  5. The fifth graph is a function, because every vertical line crosses the graph once
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7 0
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Find the slope of the line passing through the points (-7, -7) and (-3, 6).
Alenkasestr [34]

Answer:

13/4 - (13,4) - however your teacher wants you to write it out.

Step-by-step explanation:

Rise (y) over Run (x)

Equation:

y2 - y1

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x2 - x1

Inputting the numbers, 6 - -7 (aka 6+7) over -3 - -7 (aka -3+7)

6+7 = 13

-3+7 = 4

13/4 - The line is rising moving towards the right.

Hope I helped!

5 0
3 years ago
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