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kolezko [41]
3 years ago
12

Use the encrypting congruence c ≡ (7p + 12) mod 26 to code the message PARALLEL LINES.

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:  PARALLEL LINES  should be coded as "TSHSRRUR RWFUO"

Step-by-step explanation:

Since we have given that

PARALLEL LINES

As we know that according to alphabets,

P is at 16

A is at 1

R is at 18

L is at 12

E is at 5

N is at 14

S is at 19

And we have given that

c \equiv(7p+12)\ mod 26

So, P becomes :

c\equiv (7\times 16+12)\ mod\ 26=124\ mod\ 26=20\ mod\ 26=T

A becomes

c\equiv (7\times 1+12)\ mod\ 26=19\ mod\ 26=S

S becomes

c\equiv (7\times 19+12)\ mod\ 26=145\ mod\ 26=15\ mod\ 26=O

L becomes

c\equiv (7\times 12+12)\ mod\ 26=96\ mod\ 26=18\ mod\ 26=R

E becomes

c\equiv (7\times 5+12)\ mod\ 26=47\ mod\ 26=21\ mod\ 26=U

I becomes

c\equiv (7\times 9+12)\ mod\ 26=75\ mod\ 26=23\ mod\ 26=W

N becomes

c\equiv (7\times 14+12)\ mod\ 26=110\ mod\ 26=6\ mod\ 26=F

R becomes

c\equiv (7\times 18+12)\ mod\ 26=138\ mod\ 26=8\ mod\ 26=H

Hence, PARALLEL LINES  should be coded as "TSHSRRUR RWFUO"

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65 and 40%how many left<br>​
Korolek [52]

Answer:

16

Step-by-step explanation:

Divide 65 by 40 and then multiply it by 10. That gets you 16.25 so you have to round it because you can't have 1/4 of a person. So you'll get 16.

3 0
3 years ago
In a recent student government election, the ratio of students who voted for the winner to all the students who voted was 0.64.
Masja [62]

Answer:

80

Step-by-step explanation:

The total was 125

0.64 of them voted for the winner.

The number who voted for the winner = ratio * total

Votes for the winner = 0.64 * 125

Votes for the winner = 80

3 0
3 years ago
There are 156 students in a high school freshman class, and 2/3 of them play a sport. How many freshmen students play a sport?
navik [9.2K]

Answer:

104

Step-by-step explanation:

If you divide the total number of students by 3, then multiply the answer by 2, you will see that 104 students play sports.

156

156/3

52

52 x 2

104

Pls mark Brainliest with the crown

3 0
1 year ago
Read 2 more answers
Which justification describes the process? Step 1. 4x + 2= 10 step 2. 4x=8
blondinia [14]

Answer:

B

Step-by-step explanation:

The question you have to ask yourself is why did the 2 disappear on the left and why did the 10 decrease in the right.

Whatever you did, you didn't multiply to accomplish that, and you didn't add, both of which would have made things larger.

That leaves B and D. You have to consider D carefully. If you divide, that would make 2 smaller on the left, but it would never make the 2 disappear.

It would also reduce the 10, but the problem is that division would have to effect the x as well.

The answer is that B should be chosen. If you subtract 2 from both sides, the 2 on the left will disappear and you will reduce the 10 to 8 on the right.

I know my answer is a bit convoluted, but I hope it helps.

6 0
3 years ago
If pq = 23 and uv = 1/23, find the value of u×q×v×p. Explain which properties you used
zhannawk [14.2K]

Remember that multiplication is <em>commutative</em>, which means the order in which we multiply things doesn't matter.

The order of u × q × v × p (which we can abbreviate uqvp) isn't as important as the fact that <em>we're multiplying all four values together</em>. We could just as easily rewrite the expression as pquv, and it'd represent the same value.

To find this value then, we can simply multiply pq and uv - the values we already know - together.

If we start with the expression pq = 23, we can multiply either side by uv (taking advantage of the <em>multiplication property of equality) </em>to get

pquv = 23uv

And since we know that uv = 1/23, we can use the <em>substitution property of equality</em> to replace the uv on the right side with 1/23:

pquv = 23(1/23)

The <em>inverse property of multiplication </em>states that any number multiplied by its inverse (its reciprocal) gives us 1. 23 and 1/23 are reciprocals of each other, so 23(1/23) = 1, which means

pquv = 1

Finally, going back to the second paragraph, we can use the <em>commutative property of multiplication </em>to rearrange the left side of the equation, giving us the solution

uqvp = 1

3 0
3 years ago
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