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kirza4 [7]
3 years ago
9

Find the Interquartile Range for Marcus's data. A.4.5 B.2 C.6 D.2.5

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0
<h3>Answer:  B. 2</h3>

How I got that answer:

The data set for Marcus is

2, 3, 5, 6, 6, 6, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 9, 10, 10

The five number summary is

  • min = 2
  • Q1 = 6
  • median = 7
  • Q3 = 8
  • max = 10

So the interquartile range (IQR) is

IQR = Q3 - Q1

IQR = 8 - 6

IQR = 2

nekit [7.7K]3 years ago
3 0
Answer is b.2
Just did it
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Find the outlier of the data set<br> 3.1, 5.3, 4.3, 0.7, 5.6, 5.2, 5.8, 5.4
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An outglier is a data item which is much bigger/smaller than other data items.

The data item arranged is 0.7, 3.1, 4.3, 5.2, 5.3, 5.4, 5.6, 5.8
From the data 0.7 is much smaller than other data items.
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3 years ago
Katie is buying souvenir.gifts for her big family back home. She wants to buy everyone either a key chain or a magnet. The magne
NikAS [45]
The total number of gifts = x+y.
The inequality is:
x+y  \geq 24

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x+0.5y  \leq 20

Without graphing you can solve system by using substitution:
y = 24 - x  \\  \\ x + 0.5(24-x) = 20   \\  \\ 0.5x +12 = 20  \\  \\ x = 16 \\  \\ y = 24-16 = 8

This is one solution where the maximum x value is given.
So the most keychains that can be purchased is 16. However, because magnets are cheaper, more can be purchased as long as cost remains under 20.

If you solve both inequalities for "y", you get the upper and lower bounds for how many magnets can be purchased given a quantity of keychains.

24-x  \leq y  \leq 40 -2x \\  \\ x \leq 16

This is complete solution which gives all possible combinations.
(Graph is Attached)

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3 years ago
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hichkok12 [17]
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5 0
3 years ago
Solve the equation for a? z=mab. a)a=z+mb b)a=z-mb c)a= mb/z d)a=z/mb
Bingel [31]

Answer:

a = z/mb

Step-by-step explanation:

Given:

\displaystyle \large{z=mab}

To solve for a, divide both sides by the variables mb to isolate a-term.

\displaystyle \large{\dfrac{z}{mb}=\dfrac{mab}{mb}}

Simplify the expression and we finally have solved for a-term.

\displaystyle \large{\dfrac{z}{mb}=a}\\\\\displaystyle \large{a=\dfrac{z}{mb}}

Therefore, the answer to this question is a = z/mb.

Please let me know if you have any questions regarding my answer or explanation!

4 0
2 years ago
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