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Sedbober [7]
3 years ago
4

Which statement best explains why the atomic theory developed efficiently? Scientists ignored all previous knowledge about atoms

. Scientists had used creativity in their investigations. Scientists had only used standard methods of investigation. Scientists repeated experiments to make sure the results were correct.
Chemistry
2 answers:
Liula [17]3 years ago
8 0

''Scientists repeated experiments to make sure the results were correct” is the one statement which best explains the development of atomic theory efficiently.

Answer: Option D

<u>Explanation:</u>

The atomic theory was first postulated by Dalton and then J.J.Thomson gave the first theoretical assumption on the model of atom. In order to prove the model of J.J.Thomson correct, Rutherford did the gold foil experiment.

But the outcome of the experiment gave birth to new model of atom termed as nuclear model of atom. Then Chadwick, Neil Bohr, Sommerfeld have conducted and repeated various experiments to conclude the present atomic theory.

Thus the repeated experiments done by the scientists to make sure the results were correct is the one which best explains the development of atomic theory efficiently.

Ira Lisetskai [31]3 years ago
4 0

Scientists had used creativity in their investigations is the statement best explains why the atomic theory developed efficiently.

Answer: Option B is the correct choice for the given question.

Explanation:

The basic purpose of experimentation and research is to get conclusions as a solid base for development of theories in science which can help humanity in many other factors.

By utilizing these theories many other experiments and development can be done.  Similarly while postulating the atomic theory scientist had to experiment and research many times and had to do things creatively to get to this important theory.

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A 0.2500 g sample of an alloy reacts with to form hydrogen gas: 2Al(s) + 6H+(aq) 2Al3+(aq) + 3H2(g) Zn(s) + 2H+(aq) Zn2+(aq) + H
fenix001 [56]

<u>Answer:</u> The mass percent of zinc in the alloy is 78.68 %

<u>Explanation:</u>

We are given:

Mass of sample of alloy = 0.2500 g

Let the mass of aluminium be 'x' grams and mass of zinc will be (0.2500 - x)  g

To calculate the amount of hydrogen gas produced, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 755 mmHg  

V = Volume of the gas = 0.147 L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of hydrogen gas = ?

Putting values in above equation, we get:

755mmHg\times 0.147L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{755\times 0.147}{62.3637\times 298}=0.00597mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    .....(1)

  • <u>For Aluminium:</u>

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{x}{27}mol

The chemical equation follows:

2Al(s)+6H^+(aq.)\rightarrow 2Al^{3+}(aq.)+3H_2(g)

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, \frac{x}{27} moles of aluminium will produce = \frac{3}{2}\times \frac{x}{27}=\frac{3x}{54}mol of hydrogen gas

  • <u>For Zinc:</u>

Molar mass of zinc = 65.4 g/mol

Putting values in equation 1, we get:

\text{Moles of zinc}=\frac{(0.25-x)}{65.4}mol

The chemical equation follows:

Zn(s)+2H^+(aq.)\rightarrow Zn^{2+}(aq.)+H_2(g)

By Stoichiometry of the reaction:

1 mole of zinc produces 1 moles of hydrogen gas

So, \frac{(0.25-x)}{65.4} moles of zinc will produce = \frac{1}{1}\times \frac{(0.25-x)}{65.4}=\frac{(0.25-x)}{65.4}mol of hydrogen gas

  • <u>Equating the moles of hydrogen gas:</u>

\Rightarrow 0.00597=\frac{3x}{54}+\frac{(0.25-x)}{65.4}\\\\x=0.0533g

To calculate the mass percentage of zinc in alloy, we use the equation:

\text{Mass percent of zinc}=\frac{\text{Mass of zinc}}{\text{Mass of alloy}}\times 100

Mass of zinc = (0.2500 - x) = [0.2500 - 0.0533] = 0.1967 g

Mass of alloy = 0.2500 g

Putting values in above equation, we get:

\text{Mass percent of zinc in alloy}=\frac{0.1967g}{0.2500g}\times 100=78.68\%

Hence, the mass percent of zinc in the alloy is 78.68 %

8 0
4 years ago
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