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3 years ago

How much time is needed to deposit 1.0 g of chromium metal from an aqueous solution of crcl3 using a current of 1.5 a?

2 answers:

8 0

The metal component of the given compound, CrCl3, is chromium. The number of moles per 1 g of chromium is calculated through the equation below,

n = (1 g Cr)(1 mol Cr/51.996 g Cr)
n = 0.0192 mol Cr(3 electrons/1 mol Cr)
n = 0.0577 e-

Determine the number in charge by multiplying with Faraday's constant,

C = (0.0577 mol Cr)((1 F/1 mol e-)(96485 C/ 1F)
C = 5,566.87 C

Then, calculate time by dividing the charge with the current,

t = 5566.87 C/1.5 A
t = 3711.25 minutes
t = 61.84 hours

<span><em>Answer: 61.84 hours</em></span>

sergiy2304 [10]3 years ago

3 0

Answer:

$t=406.2s=6.77min$

Explanation:

Hello,

At first, one must compute the CrCl3 moles by using its molecular mass:

$n_{CrCl_3}=1gCrCl_3*\frac{1molCrCl_3}{152.35gCrCl_3}=0.00632molCrCl_3$

Now, we can apply the following equation to compute the requested time, based on the Faraday's constant, the involved charge and the fed current:

$C=n_{CrCl_3}*F\\C=0.00632molCrCl_3*96485\frac{C}{molCrCl_3}\\C=609.3C\\C=I*t\\t=\frac{C}{I}=\frac{609.3C}{1.5C/s} \\t=406.2s=6.77min$

Best regards.

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Strontium and chlorine combine in only one ratio: one strontium atom for every two chlorine atoms. Based on this

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The combinations of Strontium and chlorine that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.

1) The possible combinations are

4 strontium atoms and 8 chlorine

$2.7 * 10^19$ strontium atoms and $5.4 * 10^19$ chlorine atoms

2) The combinations that are not possible are

20 strontium atoms and 60 chlorine atoms

130 billion strontium atoms and 195 billion chlorine

We have to work out the ratio of Strontium and chlorine in each of the given combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.

First case:

4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.

Second case:

20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.

Third case:

$2.7 * 10^19$ strontium atoms and $5.4 * 10^19$ chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.

Fourth case:

130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.

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The reaction already balanced

<h3>Further explanation </h3>

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• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product

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Balancing C, H and the last O

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give coefficient

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H: left = a, right a+b=2c⇒1+1=2c⇒2=2c⇒c=1

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