Answer:
(a). The maximum loss of water vapor by the person is 
(b). The partial pressure of water vapor is 
Explanation:
Given that,
Temperature = 37.0°C
Volume of air = 2.00 L
Density of vapor = 44.0 g/m³
We need to calculate the maximum loss of water vapor by the person
Using formula of density

Put the value into the formula



(b). We need to calculate the partial pressure of water vapor
Using formula of pressure



Put the value into the formula



Hence, (a). The maximum loss of water vapor by the person is 
(b). The partial pressure of water vapor is 
Answer:
E = ρ ( R1²) / 2 ∈o R
Explanation:
Given data
two cylinders are parallel
distance = d
radial distance = R
d < (R2−R1)
to find out
Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants
solution
we have two parallel cylinders
so area is 2
R × l
and we apply here gauss law that is
EA = Q(enclosed) / ∈o ......1
so first we find Q(enclosed) = ρ Volume
Q(enclosed) = ρ (
R1² × l )
so put all value in equation 1
we get
EA = Q(enclosed) / ∈o
E(2
R × l) = ρ (
R1² × l ) / ∈o
so
E = ρ ( R1²) / 2 ∈o R
semiconductors ... silicon, germanium etc ...
Answer: B. I hope you get this right.