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bezimeni [28]
3 years ago
7

At which point will the riders experience centripetal acceleration?

Physics
1 answer:
Umnica [9.8K]3 years ago
3 0

As we know that centripetal acceleration is given as

a = \frac{v^2}{R}

so here we all know that radius of curvature of straight surface or flat surface is infinite or very large

So here acceleration will be zero when it move on flat surface

So here at points "w" , "x" , "z" the surface will be flat surface

and hence the observer will not experience centripetal acceleration

while at point Y the surface is curved and hence the observer will experience centripetal acceleration

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A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
3 years ago
Which of the following can provide direct current?
Akimi4 [234]
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7 0
3 years ago
1. Three vehicles are traveling at the same speed in the same direction on a 1 point
rusak2 [61]

9514 1404 393

Answer:

  The front of the black car

Explanation:

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4 0
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4 years ago
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A block sliding across a level surface has a mass of 2.5 kg and a mechanical energy of 20 joules. What is its velocity?
tia_tia [17]
Hi!

The energy of the block is 4 m/s

To calculate this, you need to use the equation for kinetic energy. The block is sliding (i.e. it's moving). If the object is sliding across a level surface, the only energy it has is kinetic energy, because there is no change in potential energy (which changes with height). So, the mechanical energy will be pure kinetic energy. The equation is the following, derived from the expression for kinetic energy:

v= \sqrt{ \frac{2*Ke}{m}}=\sqrt{ \frac{2*20 (kg*m^{2}*s^{-2}) }{2,5kg}}=4 m/s

Have a nice day!
8 0
3 years ago
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