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Vladimir [108]
3 years ago
7

Define G=GM/r^2 where symbol have their usual meaning​

Physics
2 answers:
Contact [7]3 years ago
8 0

Geraldine's location is the same as Geraldine's Mother sleeping higher than her room above the second floor.

DiKsa [7]3 years ago
4 0
It is also called acceleration due to gravity. g=G×R2M​ where G = gravitational constant. M = mass of the earth. R = radius of the earth. Hope this helps
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a car with an initial velocity of 10ms north was accelerated for 6 second until it ha a final velocity of 25ms north, what is th
koban [17]

Answer:

2 1/2 m/s^2 or 2.5m/s^2

Explanation:

From the question

final velocity v =25m/s

Initial velocity u =10m/s

time = 6 seconds

acceleration a = ?

Using the equation for linear motion

v = u + at

25 = 10 + a x 6

25 = 10 + a6

Subtract 10 from both sides

25-10 = 10 + a6 -10

25 - 10 = 10 -10 + a6

15 = a6

Divide both sides by 6

15/6 = a6/6

5/2 = a

a = 2 1/2 m/s^2 or 2.5m/s^2

8 0
3 years ago
Read 2 more answers
Which force diagram accurately represents a satellite in orbit around Earth?
Anit [1.1K]

Answer:

First choice

Explanation:

A satellite in orbit around Earth experiences only one force: the gravitational attraction exerted by the Earth on it. This force is labelled with F_g. In space, there are no other forces acting on the satellite.

The force of gravity acts as centripetal force, "pulling" the satellite towards the centre of its circular orbit. The inertia of the satellite (which has an initial velocity) tends to keep it moving straight, so the combination of these two effects (inertia and force of gravity) results into the circular motion of the satellite.

5 0
3 years ago
Read 2 more answers
answer key to Student Exploration: Feed the Monkey (Projectile Motion) page 3 Activity B Question: As the banana flies through s
murzikaleks [220]

As the banana flies through space, up the red arrow showing its path of motion takes a curved or parabolic shape.

<h3>What is a projectile?</h3>

A projectile is an object launched into space at an angle to the horizontal ground and allowed to fall freely under gravity.

The path of motion of a projectile is parabolic.

Examples of objects that are projectiles include:

  • A thrown banana
  • A kicked football
  • An arrow shot from a bow

Therefore, as the banana flies through space, up the red arrow showing its path of motion takes a curved or parabolic shape.

Learn more about projectiles at: brainly.com/question/24216590

6 0
3 years ago
Consider two thin disks, of negligible thickness, of radiusR oriented perpendicular to thex axis such that the x axis runs throu
Veseljchak [2.6K]

Complete question

The complete question is shown on the first and second uploaded image

Answer:∈

Answer to first question is shown on the second uploaded image.

Part B the Answer is:

The ratio  \frac{R}{a} is evaluated to be 49.99

Explanation:

The explanation is shown on the third ,fourth and fifth image.

7 0
4 years ago
A pitcher throws a 0.144-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just
Solnce55 [7]

(a) 12.8 kg m/s

The impulse delivered by the bat on the baseball is equal to the change in momentum of the baseball:

I=\Delta p = m(v-u)

where we have

m = 0.144 kg is the mass of the ball

v = -47 m/s is the final velocity of the ball

u = 42 m/s is the initial velocity of the ball

Substituting into the equation, we find

I=(0.144 kg)(-47 m/s-(42 m/s))=-12.8 kg m/s

And since we are interested in the magnitude only,

I=12.8 kg m/s

(b) 2.78 kN

The impulse exerted on the ball is also equal to the product between the average force and the contact time:

I=F\Delta t

where

F is the average force exerted on the ball

\Delta t=0.0046 s is the contact time

Solving the formula for F, we find

F=\frac{I}{\Delta t}=\frac{12.8 kg m/s}{0.0046 s}=2783 N = 2.78 kN

(c) The force exerted on the ball is much larger (1988 times more) than the weigth of the ball

The weight of the ball is given by

W=mg

where

m = 0.144 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the equation for W, we find

W=(0.144 kg)(9.8 m/s^2)=1.4 N

So as we see, the force exerted on the ball (2783 N) is almost 2000 times larger than the weight of the ball (1.4 N):

\frac{F}{W}=\frac{2783 N}{1.4 N}=1988

8 0
3 years ago
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