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serious [3.7K]
2 years ago
13

I need help please...

Mathematics
1 answer:
inna [77]2 years ago
4 0
Im pretty sure it is D "It will not be spread out across the entire coordinate plane because in Step 4 and Step 5, Sharon selected incorrect scales on the axes"
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calculate the perimeter of a triangle that has an area of 2340 cm2, and an in-circle with radius of 18cm.
vovangra [49]

Half of the perimeter multiplied by the radius of the inscribed circle is formula to find the area of a triangle, by using this you can see that the perimeter is 260 because 2340 / 9 = 260.

3 0
3 years ago
Solve for x.
xenn [34]

Answer:

a \: \:  x =  \frac{ -1 ±  i\sqrt{139}}{14}

Explanation:

Since this is unfactorable, use the Quadratic Formula:

x =  -b ± \frac{ \sqrt{ {b}^{2} - 4ac}}{2a}

Now, take the information and input it:

-1 ± \frac{ \sqrt{1 - 4(7)(5)}}{2(7)} \\  \\ -1 ± \frac{ \sqrt{ -139}}{ 14} = \frac{-1 ±  i\sqrt{139}}{14}

I am joyous to assist you anytime.

5 0
3 years ago
The graph of y = -5x + 1
Colt1911 [192]

y = -5x + 1

[y = mx + b     "m" is the slope, "b" is the y-intercept (the y value when x = 0)]

So your slope is -5, and your y-intercept is 1 or (0,1)


Slope = \frac{rise}{run}

Rise is the number of units you go up(+) or down(-).

Run is the number of units you go to the right.


Since your slope is -5 or \frac{-5}{1}, you go down 5 units, and to the right 1 unit.

6 0
3 years ago
Determine if the two triangles are congruent. If they are, state how you know.
blondinia [14]
All are congruent. Congruent means identical in size or shape. the different markings on the two shapes show that they are congruent. I can’t fully see number 10 so I can’t say it that one is or not
3 0
2 years ago
Tickets to a school play are $4.50 for an adult and $3.00 for a student. If 300 tickets are sold and $1087.50 collected, how man
Kryger [21]

Answer:

<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>

Step-by-step explanation:

a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}

\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}

3 0
2 years ago
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