Ca²⁺ion has a lower ratio of charge to volume.
The charge density of an ion is defined as the ratio of the charge of an ion to its volume. Scandium ion has high charge density than calcium ions. The charge density of an ion is defined as the ratio of the charge of an ion to its volume.
Charge density also depends on the size of the ion and valence electrons. The volume of an ion increases with its size. It is inversely proportional to ion volume and directly proportional to charge magnitude. Scandium and calcium are IV periodic elements with atomic numbers of 21 and 20 respectively. Scandium loses three electrons and has a +3 charge and calcium is a divalent cation. Hence, the Scandium ion has high charge density than the calcium ion.
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<span>I believe your answer is stage Meiosis.
Hope this helps!</span>
Answer: option D. Their speed in a vacuum
Explanation:
Electromagnetic waves all have same speed in vacuum. This speed has been calculated to be 3x10^8m/s.
Answer: Empirical formula of this compound is 
Explanation:
Mass of Cr= 104.0 g
Mass of O = 48.0 g
Step 1 : convert given masses into moles.
Moles of Cr =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Cr = 
For O =
Converting into simple whole number ratios by multiplying by 2
The ratio of Cr : O= 2: 3
Hence the empirical formula is 
The most likely empirical formula of this compound is 
Answer:
2.39×10¯⁵ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 8.08×10¯⁵ m
Charge (q) = 2.24×10¯⁹ C
Potential difference = 855 V
Area(A) =?
NOTE: Permittivity (ε₀) = 8.854×10¯¹² F/m
The area can be obtained as follow:
q = ε₀AV/d
2.24×10¯⁹ = 8.854×10¯¹² × A × 855 / 8.08×10¯⁵
2.24×10¯⁹ = 7.57×10¯⁹ × A / 8.08×10¯⁵
Cross multiply
7.75×10¯⁹ × A = 2.24×10¯⁹ × 8.08×10¯⁵
7.75×10¯⁹ × A = 1.81×10¯¹³
Divide both side by 7.75×10¯⁹
A = 1.81×10¯¹³ / 7.75×10¯⁹
A = 2.39×10¯⁵ m²
Thus, the area of the plate is 2.34×10¯⁵ m²