The molar mass of the unknown compound is calculated as follows
let the unknown gas be represented by letter Y
Rate of C2F4/ rate of Y = sqrt of molar mass of gas Y/ molar mass of C2F4
= (4.6 x10^-6/ 5.8 x10^-6) = sqrt of Y/ 100
remove the square root sign by squaring in both side
(4.6 x 10^-6 / 5.8 x10^-6)^2 = Y/100
= 0.629 =Y/100
multiply both side by 100
Y= 62.9 is the molar mass of unknown gas
Answer:
volume is 7.0 liters
Explanation:
We are given;
- Molarity of the aqueous solution as 2.0 M
- Moles of the solute, K₂S as 14 moles
We are required to determine the volume of the solution;
We need to know that;
Molarity = Moles ÷ volume
Therefore;
Volume = Moles ÷ Molarity
Thus;
Volume of the solution = 14 moles ÷ 2.0 M
= 7.0 L
Hence, the volume of the molar solution is 7.0 L
I believe that the answer is 11.5
