Answer:
2.39×10¯⁵ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 8.08×10¯⁵ m
Charge (q) = 2.24×10¯⁹ C
Potential difference = 855 V
Area(A) =?
NOTE: Permittivity (ε₀) = 8.854×10¯¹² F/m
The area can be obtained as follow:
q = ε₀AV/d
2.24×10¯⁹ = 8.854×10¯¹² × A × 855 / 8.08×10¯⁵
2.24×10¯⁹ = 7.57×10¯⁹ × A / 8.08×10¯⁵
Cross multiply
7.75×10¯⁹ × A = 2.24×10¯⁹ × 8.08×10¯⁵
7.75×10¯⁹ × A = 1.81×10¯¹³
Divide both side by 7.75×10¯⁹
A = 1.81×10¯¹³ / 7.75×10¯⁹
A = 2.39×10¯⁵ m²
Thus, the area of the plate is 2.34×10¯⁵ m²
