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Arlecino [84]
3 years ago
12

A chromium oxide compound contains 104.0 grams of chromium and 48.0 grams of oxygen. What is the most likely empirical formula o

f this compound?
Chemistry
1 answer:
TEA [102]3 years ago
4 0

Answer: Empirical formula of this compound is Cr_2O_3

Explanation:

Mass of Cr= 104.0 g

Mass of O = 48.0 g

Step 1 : convert given masses into moles.

Moles of Cr =\frac{\text{ given mass of Cr}}{\text{ molar mass of Cr}}= \frac{104.0g}{52g/mole}=2moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.0g}{16g/mole}=3moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Cr = \frac{2}{2}=1

For O =\frac{3}{2}=1.5

Converting into simple whole number ratios by multiplying by 2

The ratio of Cr : O= 2: 3

Hence the empirical formula is Cr_2O_3

The most likely empirical formula of this compound is Cr_2O_3

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