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yulyashka [42]
3 years ago
7

Please tell me the answer to #22

Mathematics
1 answer:
serg [7]3 years ago
4 0
22) \quad \dfrac{x-5}{3}= 2  \\  \\  \\ x-5= 2*3 \\  \\ x= 6+5 \\  \\  \boxed{x= 11}
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5
Daniel [21]

Answer:

a,c,d

Step-by-step explanation:

8 0
2 years ago
. Suppose that at UVA, 76% of all undergraduates are in the College, 10% are in Engineering, 7% are in Commerce, 3% are in Nursi
xxMikexx [17]

Answer: 34.2%

Step-by-step explanation:

76% of undergrads in The College

45% of those are male (since 55% female)

.76 x .45 = 34.2% of all undergrads are males in The College

4 0
3 years ago
What is the answer to the length of a rectangle is 5 feet more then the width and the perimeter is 22 what is is width of the re
Margaret [11]
Question:
l = 5 + w
perimeter = 22
width?

Solution:
Perimeter = 22
2(l + w)     = 22
2(5+w+w) = 22
2 (5 + 2w) = 22
     5 + 2w = 11
           2w = 6
             w = 3

The width is 3
3 0
3 years ago
Differentiate the function. f(x) = sin(9 ln(x))
gayaneshka [121]

Answer: f'(x)=\dfrac{9\cos(9\ln (x))}{x}.

Step-by-step explanation:

The given function is

f(x)=\sin(9\ln (x))

Using chain rule differentiate w.r.t. x.

f'(x)=\cos(9\ln (x))\dfrac{d}{dx}(9\ln (x))      \left[\because \dfrac{d}{dx}\sin x=\cos x\right]

f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]

f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]       \left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]

f'(x)=\dfrac{9\cos(9\ln (x))}{x}

Therefore, f'(x)=\dfrac{9\cos(9\ln (x))}{x}.

5 0
3 years ago
A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample standard deviation of $21.70. T
tensa zangetsu [6.8K]

Answer:

153.158 ; 177.642

Step-by-step explanation:

Given the following:

Sample mean (m) = 165.40

Sample standard deviation (s) = 21.70

Sample size (n) = 17

α = 98%

Confidence interval = m ± z(SE)

z at 98% = 2.326

SE = s/√n

SE = 21.70/√17 = 5.2630230

Hence,

Confidence interval = 165.40 ± 2.326(5.2630230)

165.40 - 12.241791498 OR 165.40 + 12.241791498

153.158 ; 177.642

3 0
3 years ago
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