Answer:
gexp = 3.65 m/s²
Explanation:
The value of acceleration due to gravity changes with the altitude. The following formula gives the value of acceleration due to gravity at some altitude from the sea level:
gexp = g(1 - 2h/Re)
where,
gexp = expected value of g at altitude = ?
g = acceleration due to gravity at sea level = 9.8 m/s²
h = altitude = 2000 km = 2 x 10⁶ m
Re = Radius of Earth = 6.37 x 10⁶ m
Therefore,
gexp = (9.8 m/s²)(1 - 2*2 x 10⁶ m/6.37 x 10⁶ m)
<u>gexp = 3.65 m/s²</u>
Answer:
3 seconds
Explanation:
Since h(t) represents the height and t represents the time, we can set the equation equal to 150 to find t.
-16t^2+96t+6=150
Subtract 150 from both sides to set the equation equal to 0, to find the solutions.
-16t^2+96t-144=0
Factor out -16, because all of the terms are divisible by it.
-16(t^2+6t+9)=0
Now we can focus on the terms inside the parenthesis and factor it again.
t^2-6t+9=0
We need to find two value that can be multiplied to get 9 and added to get -6.
-3 and -3 works.
Thus, we get (x-3)(x-3).
Now solve for 0.
x-3=0
x=3
The object reaches its maximum height after 3 seconds.
Answer:
Energy of wave will increase as the energy of wave is related to the amplitude of wave
Answer:
13.1 m/s
Explanation:
Given that a baseball is tossed up into the air at an initial velocity 18 m/s. The height of the baseball at time t in seconds is given by h(t) = 18t−4.9t 2 (in meters).
a) What is the average velocity for [1,1.5]?
To calculate the velocity travelled by the ball, differentiate the function.
dh/dt = 18 - 9.8t
Substitute t for 1 in the above Differential function
dh/dt = 18 - 9.8 (1)
But dh/dt = velocity
V = 18 - 9.8
V = 8.2 m/s
Average velocity = ( U + V ) / 2
Average velocity = (18 + 8.2)/2
Average velocity = 26.2/2
Average velocity = 13.1 m/s
