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zvonat [6]
3 years ago
12

Use the pump to add 250 molecules of the heavy species gas. How does the temperature change?

Chemistry
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

When you begin to add the molecules, the temperature inside the container is  300  K. After all 250 molecules have been added, the temperature inside the container is  300  K.

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Balance the following redox equation in acidic solution using the smallest integers possible and select the correct coefficient
romanna [79]

Answer:

Coefficient of H^{+}(aq) is more than 4

Explanation:

Oxidation: Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

  • Balance charge: Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)......(1)

Reduction: Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)

  • Balance Cr: Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)
  • Balance O and H in acidic medium: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)
  • Balance charge: Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l).......(2)

[3\times Equation-(1)]+Equation(2) gives balanced equation:

3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)

So coefficient of H^{+}(aq) is more than 4

3 0
2 years ago
You make an experiment to determine the percent mass of carbon in sugar. You find out that there is 46.63g of carbon in 75.00g o
Aleksandr [31]

Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.

<h3>Percentage composition</h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percentageby mass= \frac{mass of solute}{mass of solution}x100

<h3>This case</h3>

In this case, you know:

  • mass of solute= 46.63 g
  • mass of solution= 75 g

Replacing:

percentageby mass= \frac{46.63 g}{75 g}x100

Solving:

<u><em>percentage by mass= 62.17 %</em></u>

Finally, the percent composition of carbon in this sample is 62.17%.

Learn more about percent composition:

<u>brainly.com/question/24201923?referrer=searchResults</u>

<u>brainly.com/question/9779410?referrer=searchResults</u>

<u>brainly.com/question/17030163?referrer=searchResults</u>

3 0
2 years ago
How are models useful in describing how molecules are formed
Nady [450]

Answer:

The purpose of molecular modeling is to provide a three-dimensional image (either physical or software-based) that allows a chemist to better see the manner in which atoms and molecules can interact. These models can be used to interpret existing observations or to predict new chemical behavior.

Explanation:

It can describe shape and how they connect while forming the electrons.

6 0
3 years ago
A store employee first inflated a balloon with 1.53 moles of helium gas. When the customer said it needed to have a volume of 75
Leviafan [203]
The first volume milliliters are 328 mm
3 0
3 years ago
Dinitrogen tetraoxide, a colorless gas, exists in equilibrium with nitrogen dioxide, a reddish brown gas.
viktelen [127]

Explanation:

N2O4(g)  <----------> 2NO2(g)

Before proceeding,

A chemical equilibrium can be defined as a condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.

Statement 1.

This statement is false. Equilibrium is not about equal concentrations but rather zero change in concentration of the reactants and products.

Statement 2.

This statement is True in chemical equilibrium; the forward and reverse reactions occur at equal rates.

Statement 3.

This statement is False. The rate constant for the forward reaction is not equal to the rate constant of the reverse reaction.

Statement 4.

The concentration of NO2 divided by the concentration of N2O4 is NOT equal to a constant. To obtain a constant value irregardless of the concentrations, the concentration of NO2 must be squared. This comes from the stoichiometry of the reaction

Kc= [NO2]2 / [N2O4]

This statement is false.

3 0
2 years ago
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