Math Homework, correct answers only!

5 1/4 written in radical form

emmainna [20.7K]

Answer:Exact Form:

4 √ 5

Step-by-step explanation:

5 0

3 years ago

Hamburger meat is $2.19 per pound. A box of spaghetti noodles is $0.79.

Karo-lina-s [1.5K]

Answer:

(2.19 x 4) + (0.79 x 3)

Step-by-step explanation:

ok so u hv to take 2.19 and multiply it by four. Then take 0.79 and multiply it by three.

8 0

2 years ago

Read 2 more answers

- 3x + 4 and passes through the point (2,5)

Anuta_ua [19.1K]

Answer:

y=(x+13)/3

Step-by-step explanation:

the question is not quite clear, i think u mean y= -3x + 4

then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3

y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3

6 0

2 years ago

Answer For Brainliest

liq [111]

Answer:

the answer is D

Step-by-step explanation:

8 0

2 years ago

Clarinex is a drug used to treat asthma. In clinical tests of this drug, 1655 patients were treated with 5- mg doses of Clarinex

bagirrra123 [75]

Answer:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

Step-by-step explanation:

Data given and notation

n=1655 represent the random sample taken

$\hat p=0.021$ estimated proportion of interest

$p_o=0.012$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportions is higher than 0.012.:

Null hypothesis: $p \leq 0.012$

Alternative hypothesis: $p > 0.012$

When we conduct a proportion test we need to use the z statisitic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.021 -0.012}{\sqrt{\frac{0.012(1-0.012)}{1655}}}=3.363$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.363)=0.00039$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interest is significantly higher than 0.012 (1.2%)

3 0

3 years ago