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ohaa [14]
3 years ago
14

A city places 18 trash cans along a 13.5 miles stretch of beach. The trash cans are placed an equal distance apart. How many mil

es are in between each trash can?
Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

0.7941 miles

Step-by-step explanation:

I would think of this situation as a giant ruler.

The 18 trash cans can be thought of as endpoints on intervals in this giant ruler.

1--------2 --------3  --------4-----------5

If you notice the numbers that I wrote, there are five of them, but there are 4 intervals.

So we need to minus one from 18  to get  17 equal length intervals so that the trash cans are equally spaced.

Interval length = 13.5 miles / 17 intervals = 0.7941 miles

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The perimeter of the rectangle is 22 meters, and the perimeter of the triangle is 12 meters. Find the dimensions of the rectangl
lianna [129]

Answer:

Length:8 m

Width:3 m

Step-by-step explanation:

<u><em>The complete question is</em></u>

If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.

step 1

<em>Perimeter of rectangle</em>

we know that

The perimeter of rectangle is equal to

P=2(L+W)

we have

P=22\ m

so

22=2(L+W)

Simplify

11=L+W -----> equation A

step 2

Perimeter of triangle

The perimeter of triangle is equal to

P=\frac{L}{2}+W+5

P=12\ m

so

12=\frac{L}{2}+W+5

Multiply by 2 both sides

24=L+2W+10

L+2W=14 ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (8,3)

see the attached figure

therefore

The dimensions of the rectangle are

Length:8 m

Width:3 m

3 0
3 years ago
si entre 2 obreros tardan 10 días en hacer una carretera, ¿cuánto tardarán en hacer el mismo trabajo 4 obreros?
Olegator [25]

Answer:

5 dias

Step-by-step explanation:

10/2= 5

8 0
3 years ago
Read 2 more answers
For every $10 Helen takes home, her employer withholds $3 for taxes and social security. Helen's gross pay each month is $1950.
goldfiish [28.3K]

$1,671.43 I believe is the answer

3 0
3 years ago
Rue or False: Temperatures above-zero represent negative numbers. *
skelet666 [1.2K]

Answer:

False

Step-by-step explanation:

tempuratures below zero are negative.

3 0
2 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
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