The appropriate choice is
... D) x = -2 ±√7
Answer:
b = 4
r = 3
Step-by-step explanation:
r + b = 7
solve for 'r' to get r = 7-b
now substitute '7-b' for r in the second equation:
3.75(7-b) + 2.75b = 22.25
26.25 - 3.75b + 2.75b = 22.25
-b = -4
b = 4
r = 3
The simplified answer and the solution is listed below:
![\sqrt[4]{81 x^{8} y^{5} } \\ \\ = \sqrt[4]{(3)^{4} x^{8} y^{5} } \\ \\ = \sqrt[4]{(3 x^{2} y)^{4} y} \\ \\ =3 x^{2} y \sqrt[4]{y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B81%20x%5E%7B8%7D%20%20y%5E%7B5%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B4%5D%7B%283%29%5E%7B4%7D%20x%5E%7B8%7D%20%20y%5E%7B5%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D%20%5Csqrt%5B4%5D%7B%283%20x%5E%7B2%7D%20y%29%5E%7B4%7D%20y%7D%20%20%5C%5C%20%20%5C%5C%20%0A%3D3%20x%5E%7B2%7D%20y%20%5Csqrt%5B4%5D%7By%7D%20)
So in your problem where as ask to find and calculate the tallness of the statue if jake put a mirror on the ground and walk backward until he sees the top and the other data are seen on you diagram. In my calculation, the statues is nearly 65ft tall.
John's Bar 60 km away from Ben's Bar.
Doug's Bar is 40 km away from Kieran's Bar
John's Bar is 10 km nearer to Doug's Bar than Kieran's Bar
If I am to assume that these bar are in a liner position,
Ben's Bar Kieran's Bar John's Bar Doug's Bar
************* 60km*******************
*****************40 km ********************
*********30 km**************
Doug's Bar is 90 km away from Ben's Bar.
Ben to John = 60 km
John to Doug = 30 km
Ben to Doug = 60 + 30 = 90 km.
