The grandfather would be your parents.Hope it helps :)
Looking at this in terms of sets, let's call O the set of all owls, and F the set of all things that can fly. What this original statement is saying every animal that's a member of the set of all owls is also a member of the set of all things that can fly, or in other words, O⊂F (O is a subset of F). Negating this tells us that, while there's <em>at least one</em> element of O that also belongs to F, O is not contained entirely in F (O⊆F, in notation), so a good negation or our original statement might be:
<em>Not all owls can fly.</em>
-14+3/2b-(1+2/8b), then take out the blanket become -14+3/2b-1-2/8b , get 5/4b-15=0 so 5/4b=15 ,get b=15×4÷5. b=12
ANSWER
D. rotation, translation, reflection
EXPLANATION
Dilation is not a rigid motion.
When the triangle is dilated the image triangle may become bigger ( magnification) or smaller (reduction).
When the scale factor is negative 1, a congruent triangle is obtained.
Hence dilation will not always produce a congruent triangle.
Rotation, reflection and translation are rigid motions and hence will always produce a congruent triangle.
The approximate area that is within range of the motion sensor is 4975 square meters
<h3>How to determine the area of the range?</h3>
The figure is not given, however the area of the range can be calculated without the figure.
The given parameters are:
Angle, ⊕ = 135°
Radius, r = 65 meters
The area of the range is calculated using the following sector area
![A = \frac{\theta}{360} * \pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%5Ctheta%7D%7B360%7D%20%2A%20%5Cpi%20r%5E2)
This gives
![A = \frac{135}{360} * 3.14 * 65^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B135%7D%7B360%7D%20%2A%203.14%20%2A%20%2065%5E2)
Evaluate
A = 4974.9375
Approximate
A = 4975
Hence, the approximate area that is within range of the motion sensor is 4975 square meters
Read more about sector areas at:
brainly.com/question/16736105
#SPJ1