Answer:
Yes it is possible to increase the power with out changing the amount of work.
Explanation:
The power is defined by the amount of power divided by the time. This time is the one needed to do the work. We can understand this issue by analyzing an example with numeric values.
Work = 500 [J]
Time = 5 [s]
Power will be:
![Power=\frac{500}{5} \\Power=100 []watt]\\](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7B500%7D%7B5%7D%20%5C%5CPower%3D100%20%5B%5Dwatt%5D%5C%5C)
Now if we change the time to 2 seconds:
![Power = 500 [J]/2[s]\\Power = 250 [watt]\\](https://tex.z-dn.net/?f=Power%20%3D%20500%20%5BJ%5D%2F2%5Bs%5D%5C%5CPower%20%3D%20250%20%5Bwatt%5D%5C%5C)
As we can see, the power was increased without the need to change the work.
Potential: very top of the roller coaster, awaiting the drop. Kinetic: on its way down the largest drop
No, if the car were moving sideways, then the forces used would be on the horizontal axis. So the weight equation would be extraneous, unless one is determining the net force through an inclined plane
Answer:
3.5 m
Explanation:
The wording at the end is not very clear, but I am pretty sure that the question is asking for the total distance moved from the starting point. If this is the case, the answer is found by subtracting the two vectors from each other because they are in opposite directions. This gives you 3.5 m. If the question was asking for the actual total distance moved, you would just add them together and get 14.3 m, but I don't think that is what the question is asking for. Hope this helps! :)
Answer:
The material with higher modulus will stretch less than
The material with lower modulus
Explanation:
A material with a higher modulus is stiffer and has better resistance to deformation. The modulus is defined as the force per unit area required to produce a deformation or in other words the ratio of stress to strain.
E= stress/stain
Hooks law states that provided the elastic limit is not exceeded the extension e of a spring is directly proportional to the load or force attached
F=ke
Where k is the constant which gives the measure of the spring under tension
