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AleksAgata [21]
3 years ago
7

Read the scenario. A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a p

osition of 10 m south of the reference point. What is the car’s average velocity? 2 m/s south 4 m/s north 0 m/s 4 m/s south
Physics
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

4 m/s south

Explanation:

This is a pretty easy one.

Assume that the car has a reference point ragged x

We also know that the car starts moving at a point 10 m North of X. It moves steadily at a uniform velocity and ended at a position 10 m south of X.

If x is the reference point, we can infer that the car moves a total distance of, 10 m + 10 m.

Thus, the total distance moved by the car is 20 m.

It is also stated that it achieves that distance in 5 seconds.

Velocity is defined as the ratio of distance with respect to the tome taken, i.e V = d/t

Then, the velocity is

V = 20 / 5 = 4 m/s

Considering the fact that the car left and moved towards the south. We can say that it moved 4 m/s South.

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How do spectroscopes help with studying of distance stars?
Svetradugi [14.3K]

Answer:

You take the light from a star, planet or galaxy and pass it through a spectroscope, which is a bit like a prism letting you split the light into its component colours. "It lets you see the chemicals being absorbed or emitted by the light source. From this you can work out all sorts of things," says Watson

8 0
2 years ago
What force is the total force felt by an object?
skelet666 [1.2K]

Answer:

net force

Explanation:

Net force felt by an object.

6 0
3 years ago
Read 2 more answers
Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w
Alisiya [41]

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

4 0
3 years ago
If I have a picosecond laser how would that be expressed in terms of zeptoseconds? In terms of petaseconds?
kolbaska11 [484]
Picosecond = 10 ^ -12 seconds.
Zeptosecond = 10^ -18 seconsds
Petaseonds  =  10^15  seconds

To express Picoseconds into any of other two, you have to divide  10^-12 by the power index of the one in question

1Picosecond :   10^-12  /  10^-18 =    10^ (-12- 18) =  10^ (-12+18)= 10^6  zeptoseconds

1Picosecond :   10^-12  /  10^15 =    10^ (-12-15) =  10^-27  Petaseconds.

1Picosecond = 10^6  zeptoseconds

1Picosecond = 10^-27  Petaseconds




3 0
3 years ago
Sheila uses a 45N force on her bowling ball across a 15m lane. What work did she do on the bowling ball? Show your work.​
Maurinko [17]

Answer:

675J

Explanation:

Given parameters:

Force  = 45N

Distance  = 15m

Unknown:

Work done by Sheila  = ?

Solution:

Work done by a body is the amount of force applied to make a body move through a distance;

         Work done  = Force x distance

 Now;

          Work done  = 45 x 15  = 675J

6 0
2 years ago
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