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AleksAgata [21]
3 years ago
7

Read the scenario. A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a p

osition of 10 m south of the reference point. What is the car’s average velocity? 2 m/s south 4 m/s north 0 m/s 4 m/s south
Physics
1 answer:
Gennadij [26K]3 years ago
4 0

Answer:

4 m/s south

Explanation:

This is a pretty easy one.

Assume that the car has a reference point ragged x

We also know that the car starts moving at a point 10 m North of X. It moves steadily at a uniform velocity and ended at a position 10 m south of X.

If x is the reference point, we can infer that the car moves a total distance of, 10 m + 10 m.

Thus, the total distance moved by the car is 20 m.

It is also stated that it achieves that distance in 5 seconds.

Velocity is defined as the ratio of distance with respect to the tome taken, i.e V = d/t

Then, the velocity is

V = 20 / 5 = 4 m/s

Considering the fact that the car left and moved towards the south. We can say that it moved 4 m/s South.

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Explanation:

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The joule (J) is a unit of energy. Recall that energy may be converted between many different forms such as mechanical energy, t
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Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is  W = -177.275J

Explanation:

From the question we are told that

      The initial Volume is  Vi = 0.160 L

      The final volume is  V_f = 0.510L

      The external pressure is  P = 5.00 \ atm

Generally the change in volume is

           \Delta V = V_f - V_i

Substituting values we have

           \Delta V = 0.510 -0.160

                 = 0.350L

Generally workdone is mathematically represented as

           W = -P \Delta V

W is negative because the working is done on the environment by the system which is indicated by volume increase

     Substituting values

                W = - 5* 0.350

                    = -1.75 \ L \ \cdot atm

Now  1 \  L \cdot atm = 101.3J

  Therefore  W = -1.75* 101.3

                          = -177.275J

   

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