Answer:
r≈2.39
Step-by-step explanation:
The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
Learn more about Quadratic Equation from:
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Answer:
No
Step-by-step explanation:
People arent on brainly to do others work, they are here to help, NOT DO YOUR WORK
Resepect us more please. We stay on here just to help people. We take time out of our days to help people. So please dont make them do your work. They are here to help not be your personal servant.
Have a wonderful day! :)
Answer:
√30
Step-by-step explanation:
We can find the value of x by using Euclidean theorem
x^2 = 3 × 10
if x^ = 30 then x = √30
Consider the right triangle HBF. The Pythagorean theorem tells you ...
HF² = HB² + BF²
The lengths HB and BF can be determined by counting grid squares, or by subtracting coordinates. Here, it is fairly convenient to count grid squares. When we do that, we find ...
HB = 2
BF = 5
Using these values in the equation above, we get
HF² = 2² + 5²
HF² = 4 + 25 = 29
Taking the square root gives the length HF.
HF = √29