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Alex
3 years ago
11

Find general solution for y'' +y'-6y=12(e^3t+e^-2t)

Mathematics
2 answers:
garik1379 [7]3 years ago
6 0
 Homogeneous solution: <span><span>y′′</span>+<span>y′</span>−6y=0</span> yields the characteristic equation <span><span>r2</span>+r−6=0  ⇒  r=−3,2</span> So homogeneous part is <span><span>yc</span>=<span>C1</span><span>e<span>−3t</span></span>+<span>C2</span><span>e<span>2t</span></span></span>. Non-homogeneous solution: <span><span>y′′</span>+<span>y′</span>−6y=12<span>e<span>3t</span></span>+12<span>e<span>−2t</span></span></span> Use the method of undetermined coefficients. Suppose <span><span>yp</span>=A<span>e<span>3t</span></span>+B<span>e<span>−2t</span></span></span> is a solution, so you have <span><span><span><span>  yp</span>=A<span>e<span>3t</span></span>+B<span>e<span>−2t</span></span></span><span><span>y′p</span>=3A<span>e<span>3t</span></span>−2B<span>e<span>−2t</span></span></span><span><span>y′p</span>=9A<span>e<span>3t</span></span>+4B<span>e<span>−2t</span></span></span></span></span> Substitute into the original equation: <span><span><span><span>(<span>9A<span>e<span>3t</span></span>+4B<span>e<span>−2t</span></span></span>)</span>+<span>(<span>3A<span>e<span>3t</span></span>−2B<span>e<span>−2t</span></span></span>)</span>−6<span>(<span>A<span>e<span>3t</span></span>+B<span>e<span>−2t</span></span></span>)</span></span><span>6A<span>e<span>3t</span></span>−4B<span>e<span>−2t</span></span></span></span><span><span>=12<span>e<span>3t</span></span>+12<span>e<span>−2t</span></span></span><span>=12<span>e<span>3t</span></span>+12<span>e<span>−2t</span></span></span></span></span> This tells you that <span>A=2</span> and <span>B=−3</span>, and so your non-homogeneous part is <span><span>yp</span>=2<span>e<span>3t</span></span>−3<span>e<span>−2t</span></span></span>. Your final solution would be the sum of the non/homogeneous parts, or <span>y=<span>yc</span>+<span>y<span>p</span></span></span>
castortr0y [4]3 years ago
3 0
Am i correct? Your solution would be <span><span>y=<span>yc</span>+<span>yp</span></span></span>
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