Answer:
v₀ = 13.24 m / s
Explanation:
Let's use Newton's second law to find the average acceleration during the crash
F = m a
. a = F / m
a = 8000/73
a = 109.59 m / s²
Now we can use the kinematic equations to find the initial velocity, since when the velocity stops it is zero (v = 0)
v² = v₀² - 2 a x
v₀² = 2 a x
v₀ = √ 2 a x
v₀ = √ (2 109.59 0.80)
v₀ = 13.24 m / s
Answer:
187.37 m
Explanation:
The wavelength of an electromagnetic wave is given by:

where
c is the speed of light
f is the frequency
We see that the wavelength is inversely proportional to the frequency: this means that the shortest am wavelength will occur at the highest am frequency, which is

And substituting also the speed of light

We find the wavelength:

Answer:
2.56 m/s²
Explanation:
A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.
f = 1/2l√(T/μ)
where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s
f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²
m₁g = 4l²μ/T²
g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²
g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²
Answer: Option (c) is the correct answer.
Explanation:
When two or more small nuclei combine together to form a larger nuclei then this process is known as nuclear reaction.
The smaller is an atom, the more energy it requires to release an electron. This energy is known as binding energy.
Thus, when two small nuclei fuse together then there will be more binding energy as compared to when two large nuclei fuse together.
For example, fusion of two hydrogen atoms release more energy then one helium atom, and upon binding excess energy is released into the space.
Hence, we can conclude that energy is released in a nuclear fusion reaction based on mass-energy equivalence because for small nuclei, the binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus.