Answer:
C
Explanation:
because the rod is positive, it'll attract the negatives. leaving the positive to stay in the back
The average speed is (distance covered) / (time to cover the distance) .
<u>For example:</u>
The average speed for the 'car' part of her trip is
(distance covered in the car) / (time in the car) =
(120 km) / (3 hours) = 40 km per hr.
<u>Answering the question:</u>
Average speed for the whole journey is
(distance covered on the journey) / (time spent on the whole journey) =
(240 + 120 + 3) km / (4 + 3 + 1/2) hours =
363 km / 7.5 hours = <em>48.4 km per hour </em>
Good luck on the test !
Answers:
1) I saw a jogger whose velocity was about 3 m/s going straight North.
2) A car passed me at a velocity of almost 45 mles per hour, straight South.
3) I saw a dog chasing a cat. The cat was runing at about 40 km/h, but the dog barely reached 32 km/h, both 30° North of the East.
Explanation:
- <em>Velocity is a vector</em> and so you must report it using the <em>magnitude and </em>the<em> direction</em>.
- Velocity has <em>units</em> of distance (meter, kilometer, miles, among others) divided by units of time (second, minutes, hours, among others).
- The magnitude of velocity is also called <em>speed</em>, and you calculate speed (average speed) as per the formula <em>Speed = distance / time</em>.
The velocities described above have these meanings:
Velocity Magnitude (speed) units direction
3 m/s going North 3 m/s m/s North
45 m.p.h hour, South 45 miles per hour miles/h South.
40 km/h 30° North of East 40 km/h km/h 30° North of East
40 km/h 30° North of East 35 km/h km/h 30° North of East
Remeber, <em>vectors, like velocity, must be describe by its magnitude and direction.</em>
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If 1.21 m contains 1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.
Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion. If it gains one or more electrons, it now carries a net negative charge, and is thus "anionic."