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3 years ago

15

a telescope is oriting on a spacecraft aroudn the earth. Speed of 3.25 x 10^5 mass 7500 kg. What is the de Broglie wavelength of

the telescope. g

1 answer:

Scrat [10]3 years ago

8 0

Answer:

<em>2.72 x 10^-43 m</em>

<em></em>

Explanation:

mass of the telescope = 7500 kg

speed of the telescope = 3.25 x 10^5 m/s

de Broglie's wavelength of the telescope is given as

λ = h/mv

where

λ is the wavelength of the telescope

h is the plank's constant = 6.63 × 10-34 m^2 kg/s

m is the mass of the telescope = 7500 kg

v is speed of the telescope = 3.25 x 10^5 m/s

substituting value, we have

λ = (6.63 × 10-34)/(7500 x 3.25 x 10^5)

λ = <em>2.72 x 10^-43 m</em>

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The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from

grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

$\epsilon=-N\dfrac{d\phi}{dt}$

Where

$\dfrac{d\phi}{dt}$ is the rate of change of magnetic flux,

And $\phi=BA$

$\epsilon=-NA\dfrac{dB}{dt}$

$\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}$

$\epsilon=28.32\ V$

Using Ohm's law, $\epsilon=I\times R$

Induced current, $I=\dfrac{\epsilon}{R}$

$I=\dfrac{28.32}{1.5}$

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

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3 years ago

Calculate the power of a person that does 8kJ of work in 4 hours

anzhelika [568]

$\text{Power,}~ P = \dfrac{\text{Work done}}{\text{Time}}\\\\\\~~~~~~~~~~~~~=\dfrac{8 \times 1000~J}{4 \times 3600~ s}\\\\\\~~~~~~~~~~~~~~=\dfrac{80}{144}\\\\\\~~~~~~~~~~~~~~=0.56~ W$

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2 years ago

Read 2 more answers

On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik

Anon25 [30]

a) $4.62\cdot 10^{14} J$

b) 0.110 megatons

c) 8.46 bombs

Explanation:

a)

The energy lost by the meteorite is equal to the difference between its final kinetic energy and its initial kinetic energy:

$\Delta K=K_f-K_i$

Which can be rewritten as:

$\Delta K=\frac{1}{2}mv^2-\frac{1}{2}mu^2$

where:

$m=3.2\cdot 10^6 kg$ is the mass of the meteorite

$v=0$ is the final speed of the meteorite

$u=17 km/s = 17,000 m/s$ is the initial speed of the meteorite

Substituting the values into the equation, we found the loss in energy of the meteorite:

$\Delta K=0-\frac{1}{2}(3.2\cdot 10^6)(17000)^2=-4.62\cdot 10^{14} J$

So, the energy lost by the meteorite is $4.62\cdot 10^{14} J$

b)

The energy equivalent to 1 megaton of TNT is

$E_{TNT}=4.2\cdot 10^{15} J$

Here the energy lost by the meteorite is

$E=4.62\cdot 10^{14} J$

Therefore, in order to write the energy lost by the meteorite as a multiple of the energy of 1 megaton of TNT, we have to divide the energy lost by the meteorite by the energy equivalent to 1 TNT; we find:

$\frac{E}{E_{TNT}}=\frac{4.62\cdot 10^{14}}{4.2\cdot 10^{15}}=0.110$

So, the energy lost by the meteorite corresponds to 0.110 megatons.

c)

The energy of one atomic bomb explosion in Hiroshima is equal to

$E'=13 kt$ (13 kilotons)

which corresponds to

$E'=0.013 Mt$ (0.013 megatons)

Here the energy of the meteorite is equal to

$E=0.110 Mt$ (0.110 megatons)

Therefore, we can find how many Hiroshima bombs are equivalent to teh meteorite impact by using the following rules of three:

$\frac{1 bomb}{0.013 Mt}=\frac{x bombs}{0.110 Mt}\\x=\frac{1\cdot 0.110}{0.013}=8.46$

So, 8.46 bombs.

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3 years ago

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KatRina [158]

Answer:

Its answer d honey

Explanation:

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2 years ago

What is the magnetic force value due to 3.5nanocoloumb charge moves to the

sertanlavr [38]

The force on the charge is 1.1×10⁻⁸ N.

<h3>What is force?</h3>

Force can be defined as the product of the mass of a body and its acceleration

To calculate the force on the charge, we use the formula below.

Formula:

F = qvBsin∅............. Equation 1

Where:

q = charge
v = velocity
B = magnetic field
∅ = Angle.

From the question,

Given:

B = 25 mT = 0.025 T
v = 250 m/s
q = 3.5 nC = 3.5×10⁻⁹ C
∅ = 30°

Substitute the given values into equation 1

F = (0.025)(250)(3.5×10⁻⁹)(sin30°)

F = 1.093×10⁻⁸ N
F ≈ 1.1×10⁻⁸ N

Hence, the force on the charge is 1.1×10⁻⁸ N.

Learn more about force here: brainly.com/question/12970081

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2 years ago