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Lelechka [254]
3 years ago
6

The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy

have at first
Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

Aziz's money was $30

Osman's  money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's  money

we know that

\frac{x}{y}=\frac{2}{1}

x=2y ------> equation A

\frac{x-10}{y}=\frac{4}{3} -----> equation B

substitute equation A in equation B and solve for y

\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15

Find the value of x

x=2(15)=30

therefore

At first

Aziz's money was $30

Osman's  money was $15

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solniwko [45]

Answer:

y = 1x - 4

Step-by-step explanation:

You have to solve for the x intercept on the equation

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That is the x intercept for that equation.

Then solve for the y intercept on the equation

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That is the x intercept for that equation.

Use that to find slope for point slope form

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3 years ago
a 96 ounce container of orange juice costs $4.80. at what price should a 128 ounce container be sold in order for the unit rate
Hunter-Best [27]
4.8 / 96 = x / 120
96x = 576
x = 576/96
x = 6

check :
unit rate for 96 oz container at 4.80 = 4.80/96 = 0.05 per oz
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Basically ur looking for an equivalent fraction (and that is what proportions are...this will reduce to the same unit rate. So ur answer is $ 6.00

5 0
3 years ago
Help me please and thank you ​
goldenfox [79]
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