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Lelechka [254]
2 years ago
6

The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy

have at first
Mathematics
1 answer:
Dvinal [7]2 years ago
8 0

Answer:

Aziz's money was $30

Osman's  money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's  money

we know that

\frac{x}{y}=\frac{2}{1}

x=2y ------> equation A

\frac{x-10}{y}=\frac{4}{3} -----> equation B

substitute equation A in equation B and solve for y

\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15

Find the value of x

x=2(15)=30

therefore

At first

Aziz's money was $30

Osman's  money was $15

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