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Lelechka [254]
3 years ago
6

The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy

have at first
Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

Aziz's money was $30

Osman's  money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's  money

we know that

\frac{x}{y}=\frac{2}{1}

x=2y ------> equation A

\frac{x-10}{y}=\frac{4}{3} -----> equation B

substitute equation A in equation B and solve for y

\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15

Find the value of x

x=2(15)=30

therefore

At first

Aziz's money was $30

Osman's  money was $15

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A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 16 cm long and 4 cm wide. The di
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3 0
3 years ago
3/5 of a number is 162. Work out the number. How do I do this AQA question?
stiks02 [169]

Answer:

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3 0
4 years ago
Read 2 more answers
Write a mixed number 27/4
gayaneshka [121]
To find a mixed number, find how many times the denominator goes into the numerator evenly.

In this case, 4 can go into 27 without going over 6 times.
6 x 4 = 24.

Now we put that as the whole number.

6

We find out what numbers are left over, and place that as the numerator.

27 - 24 = 3.

Alright. 3 is the numerator.

6 3/

Finally, keep the denominator the same.

6 3/4.

Hope this helped!


7 0
3 years ago
Read 2 more answers
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