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2 years ago

How do I do algebra?

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

7 0

You multiply and add like terms, depending on the equation that you have

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1. Under absorption costing, how much fixed manufacturing overhead cost is included in the company's inventory at the end of las

Jobisdone [24]

Answer:

$5,200 a fixed manufacturing overhead cost is included in the company's inventory at the end of last year.

Income Statement is Prepared in an MS Excel File Attached With this answer Please find it.

Step-by-step explanation:

Fixed Manufacturing Overhead = Total Fixed manufacturing Overhead x Units in ending inventory / Units produced

Fixed Manufacturing Overhead = 65,000 x 20 / 250 = $5,200

File Attached.

There is a Difference of $5,200 in net operating income between the two costing methods. The amount of fixed asset assigned to closing inventory.

Download xlsx

3 0

3 years ago

Gavin had $5460.40 that he divided into tow bank accounts. he deposited 3/8 into a savings account. he deposited the rest into h

Ipatiy [6.2K]

(5460.4)(3/8) = 2,047.65 to savings

5460.4 - 2,047.65 = 3,412.75 checking

4 0

3 years ago

If the gradient of a line, A, is 4, what is the gradient of a line which is perpendicular to A?

Ne4ueva [31]

Answer:

m = - 1/4

Step-by-step explanation:

When two line is perpendicular to each other the product of them is - 1

So let the other line be B

Gradient of B = t

Gradient of A = 4

$t \times 4 = - 1 \\ t = - \frac{1}{4}$

therefore m = - 1/4

8 0

2 years ago

The Stock Market Alexander is a stockbroker. He earns 14% commission each week. Last week, he sold $4,500 worth of stocks. How m

AlexFokin [52]

Answer: last week he made $630

Step-by-step explanation:

14% of 4500 is 630

8 0

2 years ago

Number 5 ABC or D? Please help

RoseWind [281]

Answer:

Step-by-step explanation:

you want to solve it out

start with multiplying z to each. you don't multiply it to the 6 because it is in the same parenthesis set, but you multiply it to everything in the other set. After multiplying, you get: $2z^3$ , $3z^{2}$ , $5z$

now do that to the 6. After multiplying you get: $12z^{2}$ , $18z$ , $30$

now set it all next to each other $2z^3$ + $3z^{2}$ + $5z$ + $12z^{2}$ + $18z$ + $30$

now combine like terms. start with the to the highest power. since there is only one that has a third power, you put that one first. then you combine the squared ones, and so forth.

work combining the squares: $3z^{2} + 12z^{2} = 15z^{2}$

work combing the single z's: $5z + 18z = 23z$

to get this: $2z^3$ + $15z^{2}$ + $23z$ + $30$

so, the answer is D

4 0

2 years ago