2 years ago

Find the product of (2a + 3b) (2a + 3b) using identities

Mathematics

1 answer:

Step2247 [10]2 years ago

7 0

Answer:

4a^2 + 12ab + 9b^2.

Step-by-step explanation:

Use the identity (a + b)(a + b) = a^2 + 2ab + b^2 :

(2a + 3b)(2a + 3b)

= (2a)^2 + 2*(2a)(3b) + (3b)^2

= 4a^2 + 12ab + 9b^2.

You might be interested in

Find the derivative of f(x)= e^(4x) + e^-(4x)

ololo11 [35]

Answer:

$f'(x)=4e^{4x} -4e^{-4x}$

Step-by-step explanation:

To find this derivative, we will need to use the chain rule.

As there is a variable in the exponent we can use this formula:

$f'(x)=u'e^u$

In this case, $u=4x$ and $u=-4x$

This means that $u'=4$ and $u'=-4$ respectively

This gives us $f'(x)=4e^{4x} -4e^{-4x}$

4 0

2 years ago

Read 2 more answers

Dexter’s aquarium holds 4.5 gallons of water. He needs to add some chemicals to balance the pH level in the aquarium. However, t

Sati [7]

Answer:

the answer is d 17.1 L

Step-by-step explanation:

8 0

2 years ago

Applying Inverse Properties In Exercise,apply the inverse properties of logarithmic and exponential functions to simplify the ex

Kryger [21]

Answer:

$x^3-8$

Step-by-step explanation:

apply the inverse properties of logarithmic and exponential functions to simplify

$- 8 + e^{lnx^3}$

Inverse property of log says that

$e^{ln(x)=x$

we apply this property in our problem. ln has same base 'e' . so ln and e gets cancelled

$e^{ln(x^3)=x^3$

$- 8 + e^{lnx^3}$

$- 8 +x^3$

$x^3-8$

4 0

2 years ago

What is 40 /6 in fraction

Serhud [2]

Well I'm assuming that you want me to simplify the fraction 40/6. Since 40 can go into 6 multiple times, this fraction is going to be a mixed number.
40/6 in simplest form is 6 2/3. Hope I helped!

3 0

3 years ago

Can someone please solve this

Svetradugi [14.3K]

Answer:

The answer is the 3rd one.

Step-by-step explanation:

3 times 3 is 9

4 times 4 is 16

13 is in between those 2 numbers

4 0

2 years ago

Read 2 more answers

Find the product of (2a + 3b) (2a + 3b) using identities​

Find the product of (2a + 3b) (2a + 3b) using identities