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(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
Answer:
1) Greater than zero, and equal to the rate of the reverse reaction
2) Greater than zero, but less than the rate of the reverse reaction
3) Greater than zero, and equal to the rate of the reverse reaction
Explanation:
A reaction system is said to be in equilibrium when the rate of forward reaction is equal to the rate of reverse reaction.
Before we remove HCH3CO2 from the system, the system was in equilibrium. Recall that when a system is in equilibrium, the rate of forward reaction is equal to the rate of reverse reaction. The rate of reaction is greater than zero because products are being formed as the reactants interact with each other.
When HCH3CO2 is removed from the system, the equilibrium position shifts towards the left hand side hence the rate of reverse reaction is greater than the rate of forward reaction.
When the system attains equilibrium again, the rates of forward and reverse reaction become equal.
