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3 years ago

Water can form a solution by mixing with:

Chemistry

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Explanation:

Solid, liquids and gases

Anna35 [415]3 years ago

4 0

Answer:

Solid, liquids and gases

Explanation:

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All atoms of a given element are identical was proven wrong because of the existence or

vagabundo [1.1K]

Answer:

they are all similar

Explanation:

6 0

3 years ago

The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem

Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

$R=0.08205L.atm/mol.K$

$R=8.3145L.kPa/mol.K$

$R=8.3145J/mol.K$

$R=1.987cal/mol.K$

$R=0.08314L.bar/mol.K$

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

3 0

3 years ago

Can you help me please, I’ll mark brainliest.

GrogVix [38]

Answer:

i think A

Explanation:

6 0

3 years ago

If 5 grams of co and 5 grams of o2 are combined according to the reaction 2co o2 --> 2co2, which is the limiting reagent?

IrinaK [193]

When 5 grams of CO and 5grams of O₂ is combined according to the reaction 2CO + O₂ ----------> 2CO₂ then Limiting reagent is CO.

Limiting reagent is the reactant that get used up in the reaction first.

According to the given reaction:

2CO + O₂ ----------> 2CO₂

5g 5g

∴ Molar mass of CO = Molar mass of C + Molar mass of O

⇒ Molar mass of CO = 14 + 16

⇒ Molar mass of CO = 28g

∴ Molar mass of O₂ = 16(2) = 32g

∴ Molar mass of CO₂ = Molar mass of C + 2(Molar mass of O)

⇒ Molar mass of CO₂ = 14 + 2(16)

⇒Molar mass of CO₂ =44g

Let's find out the moles of CO and O₂

∴ Moles = Given mass / Molar mass

⇒ moles of CO = 5/28 = 0.17

⇒ moles of O₂ = 5/32 = 0.15

For finding out the Limiting Reagent, we will divide the number of moles with the stiochiometry of the given reaction.

⇒ For CO = Moles/ stiochiometry = 0.17/2 = 0.085

⇒ For O₂ = Moles/ stiochiometry = 0.15/1 = 0.15

Since, the ratio of number of moles with the stiochiometry is less for CO hence it is the Limiting reagent, i.e. it will get used up in the reaction first.

Hence, the Limiting reagent for the reaction is CO.

Learn more about Limiting reagent here, brainly.com/question/11848702

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1 year ago

What viral components might serve as good targets for the design of antiviral chemicals?

densk [106]

Specific events in virus replication identified as targets for antiviral agents are viral adsorption, penetration, uncoating, and viral nucleic acid synthesis as well as viral protein synthesis.

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2 years ago