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KiRa [710]
3 years ago
9

Water can form a solution by mixing with:

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Explanation:

Solid, liquids and gases

Anna35 [415]3 years ago
4 0

Answer:

Solid, liquids and gases

Explanation:

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What is the molecular formula of the compound whose molar mass is 90.08 g/mol and empirical formula is CH2O??
KIM [24]
Let (CH2O)n be molecular formula,
(12+1+1+16)n=90.08
30n=90.08
n=3
molecular formula: (CH2O) 3= C3H6O3
7 0
3 years ago
1. A substance, A₂B, has the composition by mass of 60% A and 40% B. What is the composition of AB₂ by mass?
Lubov Fominskaja [6]
This may help you
Use an arbitrary mass, 100 g is an easy number to work with. 60% of 100 g is 60 g, there are two A's. Each A is 30 g 40 g is B, and there is only one, so B is 40 g. <span>A<span>B2</span></span>, would have a mass of 30 g + 2*40 g = 110 g The new percent by mass composition of A is: <span><span><span>30g</span><span>110g</span></span>∗100%=27.3%</span> The new percent by mass composition of B is: <span><span><span><span>80g</span><span>110g</span></span>∗100%=72.7%</span></span>
8 0
3 years ago
7. Allicin, C6H65,0, is the compound that gives garlic its odor. A sample of allicin contains 3.0 X 1021 atoms of carbon. How ma
Leona [35]
N(C): N(H)=n(C): n(H)=6: 10
3×10²¹: x=6: 10
x=5×10²¹
4 0
2 years ago
What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 and M_2 are molarities of concentrated and diluted solutions and V_1 and V_2 are their respective volumes.

M_1 = 1.10M

M_2 = 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

V_1 = ?

V_2 = 525 mL

Let's plug in the given values in the formula:

1.10M(V_1)=0.005M(525mL)

V_1=(\frac{0.005M*525mL}{1.10M})

V_1=2.39mL

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

7 0
3 years ago
A compound is found to contain 50. 05% sulfur and 49. 95% oxygen by mass. What is the empirical formula for this compound? SO S2
jekas [21]

The empirical formula for the given compound has been \rm SO_2. Thus, option C is correct.

The empirical formula has been the whole unit ratio of the elements in the formula unit.

<h3>Computation for the Empirical formula</h3>

The given mass of Sulfur has been, 50.05 g

The given mass of oxygen has been 49.95 g.

The moles of elements in the sample has been given by:

\rm Moles=\dfrac{Mass}{Molar\;mass}

  • Moles of Sulfur:

\rm Moles\;S=\dfrac{50.05}{32}\\&#10; Moles\;S=1.56\;mol

The moles of sulfur in the unit has been 1.56 mol.

  • Moles of Oxygen:

\rm Moles\;O=\dfrac{49.95}{16} \\&#10;Moles\;O=3.12\;mol

The moles of oxygen in the unit has been 3.12 mol.

The empirical formula unit has been given as:

\rm S_{1.56}O_{3.12}=SO_2

Thus, the empirical formula for the given compound has been \rm SO_2. Thus, option C is correct.

Learn more about empirical formula, here:

brainly.com/question/11588623

8 0
2 years ago
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