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Sveta_85 [38]
3 years ago
13

A 2.741 g sample of a new organic material is combusted in a bomb calorimeter. the temperature of the calorimeter and its conten

ts increase from 24.33 °c to 28.60 °c. the heat capacity (calorimeter constant) of the calorimeter is 25.57 kj/°c, what is the heat of combustion per gram of the material?
Chemistry
1 answer:
lakkis [162]3 years ago
7 0
(the heat bomb calorimeter gained)=(the heat material A gave)
r.h.s=25.57 kJ/⁰C * (26.80-24.33)= 63.16 kJ
2.741g of material A made 63.16kJ
the heat of combustion per gram = 63.16/2.741 kJ/g =24.04kJ/g
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Answer:

ertyuioekgdctifrofy?

Explanation:

7 0
3 years ago
if a balloon had an initial volume of 100ml at pressure of 3.2 atm and the pressure was decreased to 1.9 atm, what would the new
hram777 [196]

Answer:

168.4 mL

Explanation:

Data Given

initial volume V1 of gas in balloon = 100 mL

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final pressure P2 of gas in balloon = 1.9 atm

final volume V2 of gas in balloon = ?

Solution:

This problem will be solved by using Boyle's law equation at constant Temperature.

The formula used

                  P1V1 = P2V2

As we have to find out Volume, so rearrange the above equation

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Put value from the data given

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4 0
3 years ago
Gallium has two naturally occurring isotopes with the following masses and natural abundances: Isotope Mass ( amu ) Abundance (%
ICE Princess25 [194]
The formula for determination of atomic mass given the mass of isotopes and relative abundance is:

Ar = ∑(mass * abundance) / 100
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4 0
3 years ago
What pattern do we see when looking at the fossil record? *
iogann1982 [59]

Answer:

Organisms become more complex over time.

Explanation:

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3 0
3 years ago
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UNO [17]
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6 0
3 years ago
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